Automating Subscription Creation with Azure Functions

Question

In modern cloud environments, automating routine tasks is key to efficiency and scalability. Azure Functions, a serverless compute service, provides a powerful platform for automating tasks within the Azure ecosystem. One common use case for Azure Functions is automating the creation of Azure subscriptions.

I'm trying to create an azure function using python which able to create a subscription automatically.

So can anyone help regarding, which type of permissions I needed.

I have attached the code.

# Authenticate with service principal credentials
    credentials = ServicePrincipalCredentials(
        client_id="

Answer 1

To create an Azure Function in your Azure subscription using Python, you’ll need the Contributor role. This role is required to perform most function app-level tasks. You can assign this role at different levels:

1. Subscription Level: This allows the service principal (or user) to create and manage resources across the entire subscription.
2. Resource Group Level: This restricts the scope to a specific resource group within the subscription.
3. Resource Level: This limits the permissions to a specific resource (e.g., the Azure Function itself).

Here’s how you can assign the Contributor role:

1. Azure Portal:
   • Go to the Azure portal.
   • Navigate to the subscription where you want to create the Azure Function.
   • Click on Access control (IAM).
   • Add a new role assignment with the Contributor role and specify the service principal or user.
   Azure CLI:
   • Use the following command to assign the Contributor role at the subscription level:

         az role assignment create --assignee <service-principal-id-or-user-id> --role Contributor --scope /subscriptions/<subscription-id>
   

     - Replace `<service-principal-id-or-user-id>` and `<subscription-id>` with the appropriate values.
   
     **Python Code**:
   
        - If you’re creating the Azure Function programmatically using Python, ensure that the service principal (or user) you’re using has the **Contributor** role assigned.
   

Remember to replace placeholders like <service-principal-id-or-user-id> and <subscription-id> with actual values. Once you have the necessary permissions, your Python code should be able to create the Azure Function in the specified subscription1.To create an Azure Function in your Azure subscription using Python, you’ll need the Contributor role. This role is required to perform most function app-level tasks. You can assign this role at different levels:

1. Subscription Level: This allows the service principal (or user) to create and manage resources across the entire subscription.
2. Resource Group Level: This restricts the scope to a specific resource group within the subscription.
3. Resource Level: This limits the permissions to a specific resource (e.g., the Azure Function itself).

Here’s how you can assign the Contributor role:

Azure Portal:

• Go to the Azure portal.
  • Navigate to the subscription where you want to create the Azure Function.
    • Click on Access control (IAM).
      • Add a new role assignment with the Contributor role and specify the service principal or user.
      Azure CLI:

      - Use the following command to assign the **Contributor** role at the subscription level:
      
      ```
      az role assignment create --assignee <service-principal-id-or-user-id> --role Contributor --scope /subscriptions/<subscription-id>
      ```
      
         - Replace `<service-principal-id-or-user-id>` and `<subscription-id>` with the appropriate values.
      
         **Python Code**:
      
            - If you’re creating the Azure Function programmatically using Python, ensure that the service principal (or user) you’re using has the **Contributor** role assigned.
      

Remember to replace placeholders like <service-principal-id-or-user-id> and <subscription-id> with actual values. Once you have the necessary permissions, your Python code should be able to create the Azure Function in the specified subscription1.