How to get the position of NotifyIcon at runtime?

Question

Hi, I want to retrieve the location and size of notifyIcon whenever it be clicked. The purpose is to set the application UI above the notifyIcon like the below photo.

Please show me how I can do this with C#.

Thank you!

Answer 1

Hi @Việt Trần , Welcome to Microsoft Q&A,

You can achieve this function through the MouseClick event of NotifyIcon. When the NotifyIcon is clicked, you can get the position of the mouse and set the position of the application UI accordingly.

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;

namespace xxx
{
     public partial class Form1 : Form
     {
         private NotifyIcon notifyIcon;
         public Form1()
         {
             InitializeComponent();
             InitializeNotifyIcon();
         }
         private void InitializeNotifyIcon()
         {
             notifyIcon = new NotifyIcon();
             notifyIcon.Icon = SystemIcons.Information;
             notifyIcon.Text = "NotifyIcon Demo";
             notifyIcon.Visible = true;
             notifyIcon.MouseClick += NotifyIcon_MouseClick;
         }
         private void NotifyIcon_MouseClick(object sender, MouseEventArgs e)
         {
             if (e.Button == MouseButtons.Left)
             {
                 // Get the current position of the mouse
                 Point mousePosition = Control.MousePosition;

                 // If the form is minimized, restore the form display
                 if (this.WindowState == FormWindowState.Minimized)
                     this.WindowState = FormWindowState.Normal;

                 //Display the form above notifyIcon
                 this.Location = new Point(mousePosition.X - this.Width / 2, mousePosition.Y - this.Height);
                 this.StartPosition = FormStartPosition.Manual;
                 this.Show();

               
             }
         }
     }
}

Best Regards,

Jiale

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Answer 2

I was able to catch the window with WindowFromPoint, but the size I get with GetWindowRect seems to be larger than what is displayed.

using System;
using System.Drawing;
using System.Runtime.InteropServices;
using System.Windows.Forms;

public partial class Form1 : Form
{
    private NotifyIcon notifyIcon;

    public Form1() {
        InitializeComponent();
        InitializeNotifyIcon();
    }

    private void InitializeNotifyIcon() {
        notifyIcon = new NotifyIcon();
        notifyIcon.Icon = SystemIcons.Information;
        notifyIcon.Text = "NotifyIcon Demo";
        notifyIcon.Visible = true;
        notifyIcon.MouseClick += NotifyIcon_MouseClick;
    }

    [StructLayout(LayoutKind.Sequential)]
    private struct RECT
    {
        public int Left;
        public int Top;
        public int Right;
        public int Bottom;
    }

    [DllImport("user32.dll")]
    private static extern IntPtr WindowFromPoint(Point Point);

    [DllImport("user32.dll", SetLastError = true)]
    private static extern bool GetWindowRect(IntPtr hWnd, out RECT lpRect);

    private void NotifyIcon_MouseClick(object sender, MouseEventArgs e) {
        if (e.Button == MouseButtons.Left) {
            var hwnd = WindowFromPoint(MousePosition);
            if (hwnd != IntPtr.Zero) {
                if (GetWindowRect(hwnd, out RECT rect)) {
                    var f = new Form {
                        StartPosition = FormStartPosition.Manual,
                        TransparencyKey = BackColor,
                        ControlBox = false,
                        Text = string.Empty,
                        FormBorderStyle = FormBorderStyle.FixedSingle,
                        Bounds = Rectangle.FromLTRB(rect.Left, rect.Top, rect.Right, rect.Bottom)
                    };
                    f.Show();
                }
            }
        }
    }
}