Shell Navigation doesn't render the next page on Android. Shell Current State shows DnsSafeHost - System Invalid Exception.

Question

Shell Navigation doesn't render the next page on Android. Shell Current State shows DnsSafeHost - System Invalid Exception.

The steps -

Have set the AppShell as MainPage

MainPage = new AppShell();

Routing registered for second page on AppShell.xaml.cs

Routing.RegisterRoute("secondpage", typeof(SecondPage));

1. From the initial page, tries to navigate to next page on button click

private void Button_OnClicked(object sender, EventArgs e) { Shell.Current.GoToAsync("secondpage"); }

Behavior -

The breakpoint redirects to the second page. But UI is never rendered.

When checked the current state of the Shell, I get the following result -

Shell Navigation doesn't render the next page on Android. Shell Current State shows DnsSafeHost - System Invalid Exception.

The steps -

Have set the AppShell as MainPage

MainPage = new AppShell();

Routing registered for second page on AppShell.xaml.cs

Routing.RegisterRoute("secondpage", typeof(SecondPage));

1. From the initial page, tries to navigate to next page on button click

private void Button_OnClicked(object sender, EventArgs e)
{
Shell.Current.GoToAsync("secondpage");
}

Behavior -

The breakpoint redirects to the second page. But UI is never rendered.

When checked the current state of the Shell, I get the following result -

Dns safe host - System Invalid Exception.

When checked the state when just after setting Shell, gives the same result. No crashes or errors. Just the navigation is blocked.

Answer 1

Hello,

GoToAsync is an asynchronous method, so you need to use await so that the method can execute as expected to complete this statement.

private async void Button_OnClicked(object sender, EventArgs e)
{
    await Shell.Current.GoToAsync("secondpage");
}

After testing, using this method does not cause the problem of a blank UI on the second page.

You can refer to Asynchronous programming scenarios for more information on asynchronous programming.

Best Regards,

Alec Liu.

---

If the answer is the right solution, please click "Accept Answer" and kindly upvote it. If you have extra questions about this answer, please click "Comment".

Note: Please follow the steps in our documentation to enable e-mail notifications if you want to receive the related email notification for this thread.