How to convert memory stream to FileResult

Question

I had asked to compress the image file in the following link:

https://nam.safelink.emails.azure.net/redirect/?destination=https%3A%2F%2Flearn.microsoft.com%2Fen-us%2Fanswers%2Fc%2F1646218&p=bT1iMDAyYjk0OC1hMTU3LTRhOGUtODA0MS05ODM4NTQ0N2Y2ZjEmdT1hZW8mbD0xNjQ2MjE4

I don't want to show the image. Instead, I need to save the image locally using the file result. How is this possible?

Answer 1

Hello,

In MAUI, you can use MediaPicker to select or take pictures and save them locally. You could refer to the necessary code and comments below.

Step 1. Add the following necessary permissions in the AndroidManifest.xml file of MAUI.

<uses-permission android:name="android.permission.CAMERA" />

<uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE" android:maxSdkVersion="32" />

<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" android:maxSdkVersion="32" />

<!-- Required only if your app needs to access images or photos that other apps created -->

<uses-permission android:name="android.permission.READ_MEDIA_IMAGES" />

<!-- Required only if your app needs to access videos that other apps created -->

<uses-permission android:name="android.permission.READ_MEDIA_VIDEO" />

<!-- Required only if your app needs to access audio files that other apps created -->

<uses-permission android:name="android.permission.READ_MEDIA_AUDIO" />

<queries>

	<intent>

		<action android:name="android.media.action.IMAGE_CAPTURE" />

	</intent>

</queries>

Step 2. Call MediaPicker to save the file locally.

public async Task PickPhotoAndSaveAsync()

{

    // If you need to save the captured file, you need to call the MediaPicker.Default.CapturePhotoAsync() method here

    FileResult photo = await MediaPicker.Default.PickPhotoAsync();

 

    if (photo != null)

    {

        // save the file into local storage

        string localFilePath = Path.Combine(FileSystem.CacheDirectory, photo.FileName);

 

        using Stream sourceStream = await photo.OpenReadAsync();

        using FileStream localFileStream = File.OpenWrite(localFilePath);

 

        await sourceStream.CopyToAsync(localFileStream);

    }

}

Best Regards,

Alec Liu.

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