DOS Copy Command

Question

I want to copy all files in a directory that end in "*1.zip" to the same name but ending in "*7.zip"

I tried (but it didn't work)

copy c:\users\fred\*1.zip c:\users\fred\*7.zip

Suggestions?
Thanks

Answer 1

Do all of the files to be copied have the same length
file names? If so, you can do this (example assumes
a five-character name preceding the 1):

copy ?????1.zip ?????7*

copy c:\users\fred\?????1.zip c:\users\fred\?????7*

• Wayne

Answer 2

[repost as my first try disappeared]

Unfortunately, the filenames are various lengths

If all else fails, you could of course use a rather
"cludgy" approach such as this in a bat file:

copy c:\users\fred\?1.zip c:\users\fred\?7*
copy c:\users\fred\??1.zip c:\users\fred\??7*
copy c:\users\fred\???1.zip c:\users\fred\???7*
copy c:\users\fred\????1.zip c:\users\fred\????7*
copy c:\users\fred\?????1.zip c:\users\fred\?????7*
copy c:\users\fred\??????1.zip c:\users\fred\??????7*
etc.

• Wayne

Answer 3

Try executing a .BAT file containing something like this:

@echo off
for %%f in (c:\users\fred\*1.zip) do ( call :sub "%%f" )
goto :end
:sub
set p=%~1
set p=%p:~0,-5%
set p=%p%7.zip
echo copy %1 "%p%"
:end

It displays the generated "copy" commands. Remove "echo" to copy the files effectively.

Answer 4

I hope to experiment more with these suggestions tonight or tomorrow. I'll post my results thereafter. Thank you. Fred