A family of Microsoft spreadsheet software with tools for analyzing, charting, and communicating data.
If you are not working with complex numbers then change
=IMSUB(E42,E47)
to
=E42-E47
and you won't need IMSUM either...
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i want to sum two cells e43 and e44, e43 with the formula =IMSUB(E42,E47) returning a value of 222 (correct) , and e44 with the formula =IMSUB(C39,F39) returning a value of 16 (correct); in cell e49, i am using =SUM(e43:e44); both of the referred to cells are returning correct values, but my sum is returning zero. Thoughts?
A family of Microsoft spreadsheet software with tools for analyzing, charting, and communicating data.
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If you are not working with complex numbers then change
=IMSUB(E42,E47)
to
=E42-E47
and you won't need IMSUM either...
not working with complex numbers really.
i changed to =IMSUM(e43,e44) and it works perfectly now. the result is a number, and the correct one, at that!
thanks much!
IMSUB returns a string value normally of the form "a + bi", which can only be converted to a number to add if the imaginary parts of the two complex numbers are identical (in which case the bi part is left off).
=IMSUM(E43,E44) will work (though the result will not be a number, but text), or you can array enter - enter using Ctrl-Shift-Enter:
=SUM(VALUE(E43:E44)) 'this will only work for the situation you describe....
Just curious - why are you working with complex numbers?