A family of Microsoft relational database management systems designed for ease of use.
So, I did realize the code I pasted got mangled like it did. The .Send and the response are 2 distinct thing. Try:
Private Sub zoek_op_pc_nummer_Click()
On Error GoTo Error_Handler
Dim xmlhttp As Object 'New MSXML2.XMLHTTP60
Dim myurl As String
Set xmlhttp = CreateObject("MSXML2.XMLHTTP")
myurl = "https://bwnr.nl/postcode.php?pc=3124RB&hn=60&tv=&tg=data&ac=pc2adres&ak=123456"
xmlhttp.Open "GET", myurl, False
xmlhttp.Send
MsgBox (xmlhttp.responseText)
Error_Handler_Exit:
On Error Resume Next
If Not xmlhttp Is Nothing Then Set xmlhttp = Nothing
Exit Sub
Error_Handler:
MsgBox "The following error has occured" & vbCrLf & vbCrLf & _
"Error Number: " & Err.Number & vbCrLf & _
"Error Source: zoek_op_pc_nummer_Click" & vbCrLf & _
"Error Description: " & Err.Description & _
Switch(Erl = 0, "", Erl <> 0, vbCrLf & "Line No: " & Erl) _
, vbOKOnly + vbCritical, "An Error has Occured!"
Resume Error_Handler_Exit
End Sub