Microsoft 365 and Office | Excel | For business | Windows
A family of Microsoft spreadsheet software with tools for analyzing, charting, and communicating data
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| E | F | G | H | I | J | K | H | |
|---|---|---|---|---|---|---|---|---|
| 52 | =('W:\Pub-Common\Foaming and Paint Line[Customer Requirements.xlsb.xlsx]Foaming'!E52) | 0 | 0 | 0 | 0 | 0 | =MAX(E52:I52)&IF(K52=0,65) |
A family of Microsoft spreadsheet software with tools for analyzing, charting, and communicating data
Locked Question. This question was migrated from the Microsoft Support Community. You can vote on whether it's helpful, but you can't add comments or replies or follow the question.
=IF(MAX(E52:I52)=0,65,MAX(E52:I52))
No it comes back with #NAME?
That formula causes a circular reference. Does this do what you want?
=LET(m, MAX(E52:I52), IF(m=0, 65, m))