Powershell - 2 arrays

Question

How will I write a code with 2 arrays where 1st array has 50 items and 2nd array has 7 items

Condition: for each item in Array 1 will assign 1 item from array 2, then 2nd item in array 1 and 2nd item in array 2..... and so on,

when 7th item in array 2, array 2 will reset to 1st item for item 8th in array 1.

Sample output

a = 1a
b = 2a
c = 3a
d = 4a
e = 5a
f = 6a
g = 7a
h = 1a
i = 2a
j = 3a
k = 4a
l = 5a
.........

Currently my 2nd array loop isn't working at all :(

Answer 1

 $Array1 = @('a','b','c','d','e','f','g','h','i','j','k','l','m')
 $Array2 = @('1a','2a','3a','4a')

 $A2Idx = 0                          # Point to first entry in the second array 
 Foreach ($a1 in $Array1) {
     "{0} = {1}" -f $a1, $Array2[$A2Idx]
     $A2Idx++                        # Point to the next entry in the second array 
    if ($A2Idx -eq $Array2.count) {  # At end? 
        $A2Idx = 0                   # Point back to first entry in the second array 
    }      
 }

Answer 2

Hi @jaime29 ,

maybe this helps:

$a = @('a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o')  
$b = @('1a', '2a', '3a', '4a', '5a', '6a', '7a')     
$bI = 0  
$result = @()  
Foreach ($item in $a) {  
    $result += $item, $b[$bI] -join "="  
    $bI++  
    if ($bI -eq $b.count) {   
        $bI = 0  
    }        
}  
$result  

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(If the reply was helpful please don't forget to upvote and/or accept as answer, thank you)

Regards
Andreas Baumgarten

Answer 3

Hi there,

Use the + operator to add to arrays together:

PS C:\> $a = 2,3,4

PS C:\> $b = 5,6,7

PS C:\> $c = $a + $b

PS C:\> $c

Hope this Answers all your queries , if not please do repost back .
If an Answer is helpful, please click "Accept Answer" and upvote it : )