It did not find the program already opened through the EXE running Task Scheduler

AnilkumarM 41 Reputation points

I have created an EXE to find the application named “TeklaStructures” if it already opened, then to get the model details. This application I have tested by running manually is working fine. But, when it run the EXE file through the Task Scheduler, the EXE is running fine. but it is not finding the “TeklaStructures” application and will not get details even it opened already. Why it is not finding? Thanks to anyone who can assist me.

Windows 10
Windows 10
A Microsoft operating system that runs on personal computers and tablets.
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An object-oriented and type-safe programming language that has its roots in the C family of languages and includes support for component-oriented programming.
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  1. MotoX80 32,531 Reputation points

    My EXE is not running if change the setting as you suggested.

    Why doesn't it run? What error do you get? Is that C++ code? Is it a command line program or a GUI?

    Configure the task scheduler to run a .bat file that calls your program.

    @echo Bat file starting at %date% %time%  
    C:\TheDirectoryWhereYouPutTheProgram\TheEXE.exe  /AnyArgumentThatYouPassToIt   
    @echo Program ended RC=%errorlevel%   
    @echo Bat file ending at %date% %time%  

    In the Task definition, configure it to run the program cmd.exe. In the arguments, you need to pass the /c switch, the name of the .bat file, and capture stdout and stderr.

    Like this

    cmd.exe /c C:\TheDirectoryWhereYouPutTheProgram\CallMyEXE.bat 1>c:\MyLogDirectory\MyEXE.log 2>&1  

    Here's an example of what it should look like.


    After the task runs, examine the log and see what output your program produced.

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