billing questions

C N 0 Reputation points
2026-07-24T17:58:12.5566667+00:00

I am paying $6.99 a month to Microsoft for what? I am not receiving help from Microsoft

Microsoft 365 and Office | Subscription, account, billing | For home | Windows
0 comments No comments

2 answers

Sort by: Most helpful
  1. Stefan Blom 348.5K Reputation points MVP Volunteer Moderator
    2026-07-24T18:44:20.62+00:00

    Your account at https://account.microsoft.com/services should tell you which service you are paying for, as John has already suggested.

    For more, see also https://support.microsoft.com/en-us/accounts-billing/how-to-investigate-a-billing-charge-from-microsoft .

    Was this answer helpful?

    0 comments No comments

  2. John Jefferson Doyon 83,045 Reputation points Independent Advisor
    2026-07-24T18:36:20.54+00:00

    Hi, @C N

    This forum is public, no one from here have access to your Microsoft Billing account.

    Please sign in to your Microsoft account and review these pages:

    If there's nothing listed there, check order history:

    • Please sign in to your Microsoft account’s billing page at https://account.microsoft.com/billing/orders
    • Adjust the date range to include the purchase date.
    • Then click “Show details” under each order to see what the charge is for.
    • If it doesn’t look familiar, click “Order help” and then select “How to investigate a billing charge.” Follow the prompts to investigate the billing charges and find out more about them.

    If you don’t see anything unusual, to help narrow down the issue:

    1. How did you get notified about the charge? (bank alert, email, etc.)
    2. What exactly does the charge description say in your statement?
    3. Do you have another Microsoft account (work, old email, family member) where your card might be added?

    Was this answer helpful?

    0 comments No comments

Your answer

Answers can be marked as 'Accepted' by the question author and 'Recommended' by moderators, which helps users know the answer solved the author's problem.