C# Winform: How to show context menu when user will click on datagridview button column

Question

On button click i show context menu just below the button this way.

private void button1_Click(object sender, EventArgs e)
            {
                Point screenPoint = button1.PointToScreen(new Point(button1.Left, button1.Bottom));
                if (screenPoint.Y + contextMenuStrip1.Size.Height > Screen.PrimaryScreen.WorkingArea.Height)
                {
                    contextMenuStrip1.Show(button1, new Point(0, -contextMenuStrip1.Size.Height));
                }
                else
                {
                    contextMenuStrip1.Show(button1, new Point(0, button1.Height));
                } 
            }

Now i want to show context menu when user click on button column. i guess this way i can achieve.

private void dataGridView1_MouseClick(object sender, MouseEventArgs e)
{
    if (e.Button == MouseButtons.Right)
    {
        ContextMenu m = new ContextMenu();
        m.MenuItems.Add(new MenuItem("Cut"));
        m.MenuItems.Add(new MenuItem("Copy"));
        m.MenuItems.Add(new MenuItem("Paste"));

        int currentMouseOverRow = dataGridView1.HitTest(e.X,e.Y).RowIndex;

        if (currentMouseOverRow >= 0)
        {
            m.MenuItems.Add(new MenuItem(string.Format("Do something to row {0}", currentMouseOverRow.ToString())));
        }

        m.Show(dataGridView1, new Point(e.X, e.Y));

    }
}

but the problem is here i am mention x & y this way m.Show(dataGridView1, new Point(e.X, e.Y));

but to set context menu's position dynamically when click on button column. suppose when i will click on last button column then menu will be show top of that button column and menu will be show below when there will be good space.

Here is a sample code by which i was trying to achieve this.

private void Form1_Load(object sender, EventArgs e)
{
    DataTable dt = new DataTable();
    dt.Columns.Add("ID", typeof(int));
    dt.Columns.Add("Name", typeof(string));
    dt.Columns.Add("Salary", typeof(int));

    DataRow dr = null;
    dr = dt.NewRow();
    dr[0] = 1;
    dr[1] = "Joydip";
    dr[2] = 5200;
    dt.Rows.Add(dr);

    dr = dt.NewRow();
    dr[0] = 2;
    dr[1] = "Salim";
    dr[2] = 3200;
    dt.Rows.Add(dr);

    dr = dt.NewRow();
    dr[0] = 3;
    dr[1] = "Sukumar";
    dr[2] = 6000;
    dt.Rows.Add(dr);

    dgList.AutoGenerateColumns = false;
    dgList.DataSource = dt;
    dgList.Columns[0].DataPropertyName = "ID";
    dgList.Columns[1].DataPropertyName = "Name";
    dgList.Columns[2].DataPropertyName = "Salary";

}

private void dgList_MouseClick(object sender, MouseEventArgs e)
{
    int currentMouseOverRow = dgList.HitTest(e.X, e.Y).RowIndex;
    if (currentMouseOverRow >= 0)
        contextMenuStrip1.Show(dgList, new Point(e.X, e.Y));

}

I tried also this code but no luck.

private void dgList_MouseClick(object sender, MouseEventArgs e)
{
    DataGridViewCell currentCell = (sender as DataGridView).CurrentCell;
    if (currentCell != null)
    {
        ContextMenuStrip cms = currentCell.ContextMenuStrip;
        Rectangle r = currentCell.DataGridView.GetCellDisplayRectangle(currentCell.ColumnIndex, currentCell.RowIndex, false);
        Point p = new Point(r.X + r.Width, r.Y + r.Height);
        contextMenuStrip1.Show(currentCell.DataGridView, p);
    }
}

please share some idea to position menu dynamically.

Thanks

Answer 1

Issue fixed. here the working code. Thanks

private void dgList_MouseClick(object sender, MouseEventArgs e)
{
    DataGridViewCell currentCell = (sender as DataGridView).CurrentCell;
    if (currentCell != null && currentCell.ColumnIndex==3)
    {
        ContextMenuStrip cms = currentCell.ContextMenuStrip;
        Rectangle r = currentCell.DataGridView.GetCellDisplayRectangle(currentCell.ColumnIndex, currentCell.RowIndex, false);
        Point p = new Point(r.X, r.Y + r.Height);
        contextMenuStrip1.Show(currentCell.DataGridView, p);
    }
}