system.text.json with dynamic object names

Question

I have a problem with dynamic object names. Can anyone please help me with deserializing this json into c# classes:

{
"WohnzimmerEG": {
"class": "org.openhab.core.items.ManagedItemProvider$PersistedItem",
"value": {
"groupNames": [
"EG"
],
"itemType": "Group",
"tags": [
"Room"
],
"label": "Wohnzimmer",
"category": "sofa"
}
},
"TreppenhausOG": {
"class": "org.openhab.core.items.ManagedItemProvider$PersistedItem",
"value": {
"groupNames": [],
"itemType": "Group",
"tags": [],
"label": "Treppenhaus",
"category": "door"
}
},
"Kinozimmer": {
"class": "org.openhab.core.items.ManagedItemProvider$PersistedItem",
"value": {
"groupNames": [
"OG"
],
"itemType": "Group",
"tags": [
"Location"
],
"label": "Kinozimmer",
"category": ""
}
}
}

Answer 1

Check one of approaches:

public class Data
{
    public string @class { get; set; }
    public Value value { get; set; }
}

public class Value
{
    public string[] groupNames { get; set; }
    public string itemType { get; set; }
    public string[] tags { get; set; }
    public string label { get; set; }
    public string category { get; set; }
}

. . .

Dictionary<string, Data> dictionary = JsonSerializer.Deserialize<Dictionary<string, Data>>( json );

where json is your string. See also other parameters of Deserialize.

Sample usage:

string category = dictionary["TreppenhausOG"].value.category;

If required, use "Manage NuGet Packages" window to add a reference to System.Text.Json.

Answer 2

@Bernd Schmal , Viorel-1's solution is good, I also make a code example for it, you could refer to the following code:

using System;  
using System.Collections.Generic;  
using System.IO;  
using System.Text.Json;  
  
namespace ConsoleApp1  
{  
    internal class Program  
    {  
        static void Main(string[] args)  
        {  
            string jsonstr = File.ReadAllText("D:\\1.json");  
            Root myDeserializedClass = JsonSerializer.Deserialize<Root>(jsonstr);  
  
            Console.WriteLine(myDeserializedClass.WohnzimmerEG.value.category);  
        }  
    }  
  
    public class Value  
    {  
        public List<string> groupNames { get; set; }  
        public string itemType { get; set; }  
        public List<string> tags { get; set; }  
        public string label { get; set; }  
        public string category { get; set; }  
    }  
  
    public class WohnzimmerEG  
    {  
        public string @class { get; set; }  
        public Value value { get; set; }  
    }  
  
    public class TreppenhausOG  
    {  
        public string @class { get; set; }  
        public Value value { get; set; }  
    }  
  
    public class Kinozimmer  
    {  
        public string @class { get; set; }  
        public Value value { get; set; }  
    }  
  
    public class Root  
    {  
        public WohnzimmerEG WohnzimmerEG { get; set; }  
        public TreppenhausOG TreppenhausOG { get; set; }  
        public Kinozimmer Kinozimmer { get; set; }  
    }  
}  
   

You could get the WohnzimmerEG's category like the following:

Console.WriteLine(myDeserializedClass.WohnzimmerEG.value.category);

Result:

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