nested function pointer

Question

nested function pointer

명관 송 21

Can I do the test function here?

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2 answers

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Answer 1

RLWA32 52,546

Consider the following which uses the function pointers to produce output -

#include <iostream>

void cc(void (*pFunc)())
{
    std::cout << "1\n";
    pFunc();
}

void vv()
{
    std::cout << "2\n";
}

void test(void (*pFunc)(void (*)()), void (*pFunc1)())
{
    pFunc(pFunc1);
}

int main()
{
    test(cc, vv);
    return 0;
}

RLWA32 52,546

Alternatively, look at the test2 function -

#include <iostream>

void cc(void (*pFunc)())
{
    std::cout << "1\n";
    pFunc();
}

void vv()
{
    std::cout << "2\n";
}

void test(void (*pFunc)(void (*)()), void (*pFunc1)())
{
    pFunc(pFunc1);
}

void test2(void (*pFunc)(void (*)()))
{
    pFunc(vv);
}

int main()
{
    test(cc, vv);
    test2(cc);
    return 0;
}

명관 송 21 Reputation points

2022-03-16T01:30:18.187+00:00

I want the test function to change during execution.
I wonder why a function pointer that receives a function pointer as a factor cannot be declared.
I'm non-English speaking, so I don't know how to write politely. Sorry.
명관 송 21 Reputation points

2022-03-16T02:12:50.27+00:00

I realized that I couldn't be a function pointer to hand over parameters. Then, is there only a way to hand over the two parameters?
RLWA32 52,546 Reputation points

2022-03-16T08:56:33.947+00:00

Look again at the test function in my earlier example. It takes two parameters, both of which are function pointers.

Viorel 126.9K

Consider this approach too:

void test( void( *pFunc )( ) )
{
   pFunc( );
}
. . .
int main( )
{
   test( [ ]( ) { age( c1 ); } );
   test( [ ]( ) { age( c2 ); } );
}

명관 송 21 Reputation points

2022-03-17T01:17:36.077+00:00

Thank you for the tip. ;b
명관 송 21 Reputation points

2022-03-17T01:23:05.047+00:00

Thanky you for the tip ;b

Answer 2

Hi, @명관 송
What test needs is a function pointer (which with void* function as a parameter). cc is actually not called.

snippet without error, output nothing:

#include<iostream>  
void cc(void (*pFunc)())  
{  
 std::cout << "1" << std::endl;  
}  
void vv()  
{  
 std::cout << "2" << std::endl;  
}  
void test(void (*pFunc)(void (*pFun2)()))  
{  
  
}  
int main()  
{  
 test(cc);  
}

Best regards,

Minxin Yu

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