how can i start app with a link in xamarin ios ..thanks

Question

how can i start app with a link in xamarin ios ..thanks

C#

//like this:

openapp.Testmobile://123

Answer 1

Hello,

You could use Xamarin.Essentials: Launcher in Xamarin.Forms to open other apps via URI . In iOS 9 and greater, Apple enforces what schemes an application can query for. To specify which schemes you would like to use, you must specify LSApplicationQueriesSchemes in your Info.plist file.

<key>LSApplicationQueriesSchemes</key>  
<array>  
    <string>XXX</string>   
</array>  

In Xamarin.iOS, you could use UIApplication.SharedApplication.OpenUrl(url);. Optionally, the CanOpenUrl method can be used to check if the URI schema can be handled by an application on the device: UIApplication.SharedApplication.CanOpenUrl(url);
For more details, refer to
https://developer.apple.com/documentation/uikit/uiapplication/1648685-openurl?language=objc
https://developer.apple.com/documentation/uikit/uiapplication/1622952-canopenurl?language=objc

------UPDATE------

You couldn't use Xamarin.Essentials.Browser by this way : await Xamarin.Essentials.Browser.OpenAsync("lyft://ridetype?id=lyft_line");
From the source code, we can see that Xamarin.Essentials.Browser uses SFSafariViewController to load the Uri and keep navigation awareness. But SFSafariViewController provides a visible standard interface for browsing the web, the above URI is not a web URL.

Best Regards,
Wenyan Zhang

---

If the answer is the right solution, please click "Accept Answer" and kindly upvote it. If you have extra questions about this answer, please click "Comment".
Note: Please follow the steps in our documentation to enable e-mail notifications if you want to receive the related email notification for this thread.