Detect price difference for an item

Jonathan Brotto 1,076 Reputation points
2022-03-25T21:02:10.537+00:00

I exported a query to excel but before I do it, I was wondering if I use a partition by and something like rank to create a column that indicates that all items are not the same price.

187102-image.png

SQL Server
SQL Server
A family of Microsoft relational database management and analysis systems for e-commerce, line-of-business, and data warehousing solutions.
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Transact-SQL
Transact-SQL
A Microsoft extension to the ANSI SQL language that includes procedural programming, local variables, and various support functions.
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Accepted answer
  1. Naomi 7,361 Reputation points
    2022-03-28T15:05:12.307+00:00

    Try:

    SELECT T0.DocNum as 'Doc. Number', T0.CardName, T0.NumAtCard as 'Customer PO #', 
     T1.Quantity, T1.ItemCode as 'Part Number', 
     T4.U_PCODE AS 'U_Pcode', T4.U_GACEQ AS 'U_GACEQ', T4.U_Gaceq2018 AS 'U_Gaceq2018', 
     T4.U_COO AS 'COO', T4.U_SignaPCode AS 'P-CODE Sigma', 
     T4.U_BDAF AS 'P-CODE GACEQ', T4.U_GACEQ2 AS '2018-0616-02-01', 
     T4.U_HSK AS 'H-Sick Kids', T5.FirmName,
     T1.Dscription, T1.Codebars, 
     T0.DocDate as 'Delivery Date', T0.CardCode as 'Customer Code', 
     T1.Price as 'Price', T1.Linetotal As Value, 
     T4.SalPackUn,
    case when max(T1.Price) over (partition by T1.ItemCode)<>min(T1.Price) over (partition by T1.ItemCode) then 'Different Prices' else 'Same Price' end as PriceTestOverItem   
     FROM OINV T0  
     INNER JOIN INV1 T1 ON T0.DocEntry = T1.DocEntry 
     INNER JOIN OCRD T2 ON T0.CardCOde = T2.CardCode 
     INNER JOIN OCRG T3 ON T2.GroupCode = T3.GroupCode 
     AND T3.GroupType = 'C' 
     INNER JOIN OITM T4 ON T1.ItemCode = T4.ItemCode 
     INNER JOIN OMRC T5 ON T5.FirmCode = T4.FirmCode
     WHERE T1.Quantity != 0
     AND T0.DocDate >='[%1]' AND T0.DocDate <='[%2]' and T3.GroupName = '[%3]'
    
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3 additional answers

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  1. Naomi 7,361 Reputation points
    2022-03-25T21:15:39.697+00:00

    You can use condition
    case when max(price) over (partition by item) <> min(price) over (partition by Item) then 'All items are not the same price' else 'All items are the same price' end


  2. Ronen Ariely 15,101 Reputation points
    2022-03-25T21:21:50.267+00:00

    Hi,

    (1) We cannot query image!

    Please provide queries to create the table and insert the sample data

    (2) The description is not clear to me. Please go over the points I mention in the following image and clarify

    Note! the first question should be: why these are NOT the different
    186939-image.png


  3. Bert Zhou-msft 3,421 Reputation points
    2022-03-28T07:13:58.123+00:00

    Hi,@Jonathan Brotto

    Welcome to Microsoft T-SQL Q&A Forum!

    Here I agree with NaomiNNN's approach.
    I have tested it locally, and I can find different columns after grouping. As a reminder, here you need to sort the tity column. The following are my test results:

     ;with Ranked  
     as  
     (  
    	select *,  
    	Compare_Result=case when  
    	max(P_After_Discount) over (partition by Part_Number order by tity ) <> min(P_After_Discount) over (partition by Part_Number order by tity)   
    	then 'All items are not the same price'   
    	else 'All items are the same price'   
    	end  
    	from ##test  
     )  
     select   
     * from Ranked  
    

    187423-image.png

    Note: If it does not meet your expectations, please provide the following sample statement, because my test only created some columns to achieve the results I expected.

    Best regards,
    Bert Zhou


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