How to get attribute xml from treeview winforms?

Question

There is a xml file.

   <?xml version="1.0" encoding="utf-8"?>  
   <group name="Student">  
     <value>A</value>       
     <value>B</value>  
   </group>  

I need to edit the group's name "Student". but the treeview dosen't show attribute.
How can I get the attribute? Thank you for your helping!

The treeview.

My Code.

 private void button1_Click(object sender, EventArgs e)  
 {  
     OpenFileDialog dlg = new OpenFileDialog();  
     dlg.Filter = "XML Files (*.xml)|*.xml";  
     if (dlg.ShowDialog() == DialogResult.OK)  
     {  
         try  
         {  
             this.Cursor = Cursors.WaitCursor;  
             XmlDocument xDoc = new XmlDocument();  
             xDoc.Load(dlg.FileName);  
             tvLabel.Nodes.Clear();  
             tvLabel.Nodes.Add(new TreeNode(xDoc.DocumentElement.Name));  
             TreeNode tNode = new TreeNode();  
             tNode = (TreeNode)tvLabel.Nodes[0];  
             addTreeNode(xDoc.DocumentElement, tNode);  
             tvLabel.ExpandAll();  
         }  
         catch (Exception ex)  
         {  
             MessageBox.Show(ex.Message);  
         }  
         finally  
         {  
             this.Cursor = Cursors.Default;  
         }  
     }  
 }  
 private void addTreeNode(XmlNode xmlNode, TreeNode treeNode)  
 {  
     XmlNode xNode;  
     TreeNode tNode;  
     XmlNodeList xNodeList;  
     if (xmlNode.HasChildNodes)  
     {  
         xNodeList = xmlNode.ChildNodes;  
         for (int x = 0; x <= xNodeList.Count - 1; x++)  
         {  
             xNode = xmlNode.ChildNodes[x];  
             treeNode.Nodes.Add(new TreeNode(xNode.Name));  
             tNode = treeNode.Nodes[x];  
             addTreeNode(xNode, tNode);  
         }  
     }  
     else  
         treeNode.Text = xmlNode.OuterXml.Trim();  
 }  

---------Edited April, 18----------
Let's say.
I have this kind of XMl file or more complicated one.
so I would like to see all attributes.

   <?xml version="1.0" encoding="utf-8"?>  
   <Order name="Student">  
     <group name="TES" Caption="A_TES" Display="true">  
     <group name="TOR" Caption="B_TOR" Display="true">  
     <group name="TPQ" Caption="D_TPQ" Display="false">  
     <group name="TEX" Caption="A_TEX" Display="true">  
       <item app="TAL" Page="0">ABC</item>  
   <item app="TAL" Page="0">CBD</item>  
   ...  
   ...  
   <Order name="Plan">  
     <package key="Special" Row="0" Col="0">  
       <group key="Special_VB" Row="0" Col="0">  
     <item>bing</item>   
     <item>bx</item>  

Like this picture.

Answer 1

@LooBi , Welcome to Microsoft Q&A, you could try to use XDocument to get the get attribute value from the xml.

Code:

 public string FileName { get; set; }  
    private void button1_Click(object sender, EventArgs e)  
    {  
        OpenFileDialog dlg = new OpenFileDialog();  
        dlg.Filter = "XML Files (*.xml)|*.xml";  
        if (dlg.ShowDialog() == DialogResult.OK)  
        {  
            try  
            {  
                this.Cursor = Cursors.WaitCursor;  
                XmlDocument xDoc = new XmlDocument();  
                xDoc.Load(dlg.FileName);  
                FileName= dlg.FileName;  
                tvLabel.Nodes.Clear();  
                tvLabel.Nodes.Add(new TreeNode(xDoc.DocumentElement.Name));  
                TreeNode tNode = new TreeNode();  
                tNode = (TreeNode)tvLabel.Nodes[0];  
                addTreeNode(xDoc.DocumentElement, tNode);  
                tvLabel.ExpandAll();  
            }  
            catch (Exception ex)  
            {  
                MessageBox.Show(ex.Message);  
            }  
            finally  
            {  
                this.Cursor = Cursors.Default;  
            }  
        }  
    }  
  
  
    private void addTreeNode(XmlNode xmlNode, TreeNode treeNode)  
    {  
        XmlNode xNode;  
        TreeNode tNode;  
        XmlNodeList xNodeList;  
        if (xmlNode.HasChildNodes)  
        {  
            xNodeList = xmlNode.ChildNodes;  
            for (int x = 0; x <= xNodeList.Count - 1; x++)  
            {  
                xNode = xmlNode.ChildNodes[x];  
                string nodetext = xNode.Name+": ";  
                Console.WriteLine(nodetext);  
                if(!nodetext.Contains("text"))  
                {  
                    if (xNode.Attributes.Count>0)  
                    {  
                        for (int i = 0; i < xNode.Attributes.Count; i++)  
                        {  
                            nodetext+=xNode.Attributes[i].Name+" - "+xNode.Attributes[i].Value;  
                        }  
                    }  
                }  
                  
  
  
                treeNode.Nodes.Add(new TreeNode(nodetext));  
                tNode = treeNode.Nodes[x];  
                addTreeNode(xNode, tNode);  
            }  
        }  
        else  
        {  
            string nodetext = xmlNode.Name+": ";  
            Console.WriteLine(nodetext);  
            if (!nodetext.Contains("text"))  
            {  
                if (xmlNode.Attributes.Count>0)  
                {  
                    for (int i = 0; i < xmlNode.Attributes.Count; i++)  
                    {  
                        nodetext+=xmlNode.Attributes[i].Name+" - "+xmlNode.Attributes[i].Value;  
                    }  
                }  
            }  
            else  
            {  
                nodetext=xmlNode.InnerText;  
            }  
            treeNode.Text = nodetext;  
        }  
          
    }  

Result:

Best Regards,
Jack

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