How to show all attributes in xml?

Question

I want to show all attributes in treeview with my code.
How can I develop this code? Thank you!

XDocument document;
public void button1_Click(object sender, EventArgs e)
{
    document = XDocument.Load("test.xml");
    AddNodes(document.Root, treeView1.Nodes);

    treeView1.ExpandAll();
}

public void AddNodes(XElement element, TreeNodeCollection parent)
{
    var count = element.Elements().Count();

    if (count == 0)
    {
        var node = parent.Add(element.Value);
        node.Tag = element;
    }
    else
    {
        var node = parent.Add(element.Name.ToString());
        node.Tag = element;

        foreach (var child in element.Elements())
        {
            AddNodes(child, node.Nodes);
        }
    }
}

Answer 1

@fzkim , Welcome to Microsoft Q&A, you could try the following code to show all attributes in treeview.

Code:

  public void AddNodes(XElement element, TreeNodeCollection parent)  
    {  
        var count = element.Elements().Count();  
        if (count == 0)  
        {  
            //var node = parent.Add(element.Name.ToString());  
            //node.Tag = element;  
            string attbriutename = "";  
            if (element.HasAttributes)  
            {  
              
                attbriutename = element.Name.ToString();  
                foreach (XAttribute att in element.Attributes())  
                {  
                    attbriutename += " " + att.ToString();  
                }  
            }  
            else  
            {  
                attbriutename = element.Name.ToString();  
            }  
            var node = parent.Add(attbriutename);  
            node.Nodes.Add(element.Value);  
        }  
        else  
        {  
            string attbriutename = "";  
            if(element.HasAttributes)  
            {  
                attbriutename = element.Name.ToString();  
                foreach (var item in element.Attributes())  
                {  
                    attbriutename += " "+item.ToString();  
                }  
            }  
            else  
            {  
                attbriutename = element.Name.ToString();  
            }  
            var node = parent.Add(attbriutename);  
            //node.Tag = element;  
            foreach (var child in element.Elements())  
            {  
                AddNodes(child, node.Nodes);  
              
            }  

        }  
    }  

Result in xml and treeview:

Best Regards,
Jack

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