Get DirectoryName for folder

Question

I have this script which exports a list of files and folders to a csv.

Get-ChildItem -path D:\VmWare -Recurse | Select-Object DirectoryName, Name, Extension, Length | Export-Csv -Path D:\Temp\Test.csv -Encoding Unicode -NoTypeInformation

I trying to figure out if it's possible to get DirectoryName for a folder. If I choose 'Fullname' I also get file name on files, which I don't want to.
I found this line, but I don't see how to incorporate it to the script above.

foreach {Split-Path -Path $_.Fullname -Parent | Split-Path -NoQualifier }

/api/attachments/23228-screenshot-1.jpg?platform=QnA

Answer 1

Do you want only directories in the list? If so, add the "-Directory" switch to the Get-ChildItem cmdlet.

If you want directories and files in the list, then this should help:

Get-ChildItem c:\junk -Recurse | 
    ForEach-Object {
        if ($_.PSIsContainer){
            $_.FullName
        }
        else{
            $_.DirectoryName
        }
    }

Answer 2

Make DirectoryName a calculated property:

Get-ChildItem -path D:\VmWare -Recurse |
    Select @{ N = 'DirectoryName' ; E = {
        If ( ! ( $_.PSIsContainer ))
            { $_.DirectoryName }
        Else
            { Split-Path $_.FullName }
    }}, Name, Extension, Length |
Export-Csv -Path D:\Temp\Test.csv -Encoding Unicode -NoTypeInformation

Answer 3

Hi,

According to your screenshot, are you trying to get the full path of the parent directory of a directory? If yes you may try this

Get-ChildItem -path D:\VmWare -Recurse -Directory | ForEach-Object { Split-Path -Path $_.FullName -Parent }  

Best Regards,
Ian

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