How to prompt for program to open file with using powershell

Question

Hello,

I know that Start-Process -FilePath <path to file> opens the file at path to file, however is it possible to, instead of opening with the default program, open the prompt that would open if you would right click on that file and then press Open with -> Choose another app?

Answer 1

Use openwith.

$ps = new-object System.Diagnostics.Process  
$ps.StartInfo.Filename = "openwith.exe"  
$ps.StartInfo.Arguments = "C:\temp\xxxxxxxx.txt"  
$ps.start()  

Answer 2

How to Add “Open PowerShell Here” to the Right-Click Menu for a Folder in Windows