How to split array of integers?

Question

_{Saturday, May 26, 2018 7:08 PM}

Hi there,

I have an array of integers, like:

a[0]=1; a[1]=5; a[2]=89; a[3]=125; a[4]=203

and variable divNo containing the number I have to find in that array.

If we assume that divNo is 89, array has to be split in two: first one from a[0] to a[2]=divNo=89 and second one from a[3] to a[4].

How do I do that?

Thanks a lot in advance.

Kind regards

All replies (5)

_{Saturday, May 26, 2018 8:22 PM ✅Answered}

Following will done the trick for you

class Program
{
    static void Main(string[] args)
    {
        int[] a = new[] { 1, 5, 89, 125, 203 };
        var divNo = 89;
 
        var index = Array.IndexOf(a, divNo);
 
        if (index > -1)
        {
            Split(a, index + 1, out int[] b, out int[] c);
 
            Console.WriteLine("Elements in First Array");
 
            foreach (var i in b)
            {
                Console.WriteLine(i);
            }
 
            Console.WriteLine("Elements in Second Array");
 
            foreach (var i in c)
            {
                Console.WriteLine(i);
            }
 
            Console.ReadLine();
 
        }
    }
 
    public static void Split<T>(T[] array, int index, out T[] first, out T[] second)
    {
        first = array.Take(index).ToArray();
        second = array.Skip(index).ToArray();
    }
}

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_{Saturday, June 9, 2018 5:43 PM ✅Answered}

Use LINQ

int[] numbers = new int[] { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };

var first = numbers.Take(Array.IndexOf(numbers, 6) + 1);
var rest = numbers.Skip(Array.IndexOf(numbers, 6) + 1);

---

_{Sunday, June 10, 2018 10:31 PM ✅Answered}

var first = numbers.TakeWhile(n => n <=89);

var second = numbers.SkipWhile(n => n<= 89);

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_{Saturday, May 26, 2018 9:39 PM}

Thanks a lot Nasser Malik, it works great!

Regards

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_{Monday, June 11, 2018 1:10 PM}

even better!