How to get the current project path

Question

_{Friday, January 18, 2013 11:11 AM}

i have an xml file in my project

C:\Documents and Settings\.\.\SampleXML\SampleXML\sample.xml

if i try to load this file, it is looking at C:\Documents and Settings\.\.\SampleXML\SampleXML\bin\Debug

can u help me how to load from first location which i have mentioned

All replies (7)

_{Friday, January 18, 2013 11:48 AM ✅Answered | 1 vote}

Add these characters “../” in front of you file name, based on the folder structure.  This will navigate from bin folder, in your case the code will be as

XDocument doc = XDocument.Load(@"../../sample.xml");

first set will navigate from debug to bin, send set will navigate from bin to root folder. The root will have the xml file.

sri

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_{Friday, January 18, 2013 11:13 AM}

hi  you can do like this way,

1) You can open properties and copy to Output directory =true,

2) or manually place file in debug,

By Sanz. -- If you find this post helpful then please "Vote as Helpful" and "Mark As Answer".

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_{Friday, January 18, 2013 11:14 AM}

Hi,

You mean to add XML file to your project which is present in the given path C:\Documents and Settings\.\.\SampleXML\SampleXML\bin\Debug  ?

PS.Shakeer Hussain

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_{Friday, January 18, 2013 11:15 AM}

i dont want to place dat file in Debug folder.. it should be in project path which i have mentioned

XDocument doc = XDocument.Load(@"sample.xml"); \ this is looking at bin debug folder.

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_{Friday, January 18, 2013 11:47 AM}

  var parent = System.IO.Directory.GetParent(Environment.CurrentDirectory);            var x = XDocument.Load(parent.Parent.FullName + "\\sample.xml");

This is what you need to do

By Sanz. -- If you find this post helpful then please "Vote as Helpful" and "Mark As Answer".

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_{Friday, January 18, 2013 12:06 PM}

Hi,

If I were you I would not start with figuring out a relative path, what happens when you want to move the executable or the xml file ?

I would make the default file path an application setting you configure in the app.config or give the user the opportunity to  select the file using an open filedialog

Hope this helps,

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_{Friday, April 20, 2018 2:15 PM}

Nice. never knew such shortcut exist.