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Extract the minutes of a given timestamp as integer.
For the corresponding Databricks SQL function, see minute function.
Syntax
from pyspark.databricks.sql import functions as dbf
dbf.minute(col=<col>)
Parameters
| Parameter | Type | Description |
|---|---|---|
col |
pyspark.sql.Column or str |
target date/time/timestamp column to work on. See Also -------- :meth:pyspark.sql.functions.year :meth:pyspark.sql.functions.quarter :meth:pyspark.sql.functions.month :meth:pyspark.sql.functions.day :meth:pyspark.sql.functions.hour :meth:pyspark.sql.functions.second :meth:pyspark.sql.functions.extract :meth:pyspark.sql.functions.datepart :meth:pyspark.sql.functions.date_part |
Returns
pyspark.sql.Column: minutes part of the timestamp as integer.
Examples
from pyspark.databricks.sql import functions as dbf
df = spark.createDataFrame([('2015-04-08 13:08:15',), ('2024-10-31 10:09:16',)], ['ts'])
df.select("*", dbf.typeof('ts'), dbf.minute('ts')).show()
import datetime
df = spark.createDataFrame([
(datetime.datetime(2015, 4, 8, 13, 8, 15),),
(datetime.datetime(2024, 10, 31, 10, 9, 16),)], ['ts'])
df.select("*", dbf.typeof('ts'), dbf.minute('ts')).show()
import datetime
df = spark.createDataFrame([
("13:08:15",),
("10:09:16",)], ['t']).withColumn("t", dbf.col("t").cast("time"))
df.select("*", dbf.typeof('t'), dbf.minute('t')).show()