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__shiftleft128

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Microsoft Specific

Shifts a 128-bit quantity, represented as two 64-bit quantities LowPart and HighPart, to the left by a number of bits specified by Shift and returns the high 64 bits of the result.

Syntax

unsigned __int64 __shiftleft128(
   unsigned __int64 LowPart,
   unsigned __int64 HighPart,
   unsigned char Shift
);

Parameters

LowPart
[in] The low 64 bits of the 128-bit quantity to shift.

HighPart
[in] The high 64 bits of the 128-bit quantity to shift.

Shift
[in] The number of bits to shift.

Return value

The high 64 bits of the result.

Requirements

Intrinsic Architecture
__shiftleft128 x64

Header file <intrin.h>

Remarks

The Shift value is always modulo 64 so that, for example, if you call __shiftleft128(1, 0, 64), the function will shift the low part 0 bits left and return a high part of 0 and not 1 as might otherwise be expected.

Example

// shiftleft128.c
// processor: IPF, x64
#include <stdio.h>
#include <intrin.h>

#pragma intrinsic (__shiftleft128, __shiftright128)

int main()
{
    unsigned __int64 i = 0x1I64;
    unsigned __int64 j = 0x10I64;
    unsigned __int64 ResultLowPart;
    unsigned __int64 ResultHighPart;

    ResultLowPart = i << 1;
    ResultHighPart = __shiftleft128(i, j, 1);

    // concatenate the low and high parts padded with 0's
    // to display correct hexadecimal 128 bit values
    printf_s("0x%02I64x%016I64x << 1 = 0x%02I64x%016I64x\n",
             j, i, ResultHighPart, ResultLowPart);

    ResultHighPart = j >> 1;
    ResultLowPart = __shiftright128(i, j, 1);

    printf_s("0x%02I64x%016I64x >> 1 = 0x%02I64x%016I64x\n",
             j, i, ResultHighPart, ResultLowPart);
}

0x100000000000000001 << 1 = 0x200000000000000002
0x100000000000000001 >> 1 = 0x080000000000000000

END Microsoft Specific

See also

__shiftright128
Compiler intrinsics