# DB

Returns the depreciation of an asset for a specified period using the fixed-declining balance method.

## Syntax

```
DB(<cost>, <salvage>, <life>, <period>[, <month>])
```

### Parameters

Term | Definition |
---|---|

cost | The initial cost of the asset. |

salvage | The value at the end of the depreciation (sometimes called the salvage value of the asset). This value can be 0. |

life | The number of periods over which the asset is being depreciated (sometimes called the useful life of the asset). |

period | The period for which you want to calculate the depreciation. Period must use the same units as life. Must be between 1 and life (inclusive). |

month | (Optional) The number of months in the first year. If month is omitted, it is assumed to be 12. |

## Return Value

The depreciation over the specified period.

## Remarks

The fixed-declining balance method computes depreciation at a fixed rate. DB uses the following formulas to calculate depreciation for a period:

$$(\text{cost} - \text{total depreciation from prior periods}) \times \text{rate}$$

where:

- $\text{rate} = 1 - ((\frac{\text{salvage}}{\text{cost}})^{(\frac{1}{\text{life}})})\text{, rounded to three decimal places}$

Depreciation for the first and last periods is a special case.

For the first period, DB uses this formula:

$$\frac{\text{cost} \times \text{rate} \times \text{month}}{12}$$

For the last period, DB uses this formula:

$$\frac{(\text{cost} - \text{total depreciation from prior periods}) \times \text{rate} \times (12 - \text{month})}{12}$$

period and month are rounded to the nearest integer.

An error is returned if:

- cost < 0.
- salvage < 0.
- life < 1.
- period < 1 or period > life.
- month < 1 or month > 12.

This function is not supported for use in DirectQuery mode when used in calculated columns or row-level security (RLS) rules.

## Examples

### Example 1

The following DAX query:

```
EVALUATE
{
DB(1000000, 0, 6, 1, 2)
}
```

Returns an asset's depreciation in the last two months of the first year, assuming it will be worth \$0 after 6 years.

[Value] |
---|

166666.666666667 |

### Example 2

The following calculates the total depreciation of all assets in different years over their lifetimes. Here, the first year only includes 7 months of depreciation, and the last year only includes 5 months.

```
DEFINE
VAR NumDepreciationPeriods = MAX(Asset[LifeTimeYears])+1
VAR DepreciationPeriods = GENERATESERIES(1, NumDepreciationPeriods)
EVALUATE
ADDCOLUMNS (
DepreciationPeriods,
"Current Period Total Depreciation",
SUMX (
FILTER (
Asset,
[Value] <= [LifetimeYears]+1
),
DB([InitialCost], [SalvageValue], [LifetimeYears], [Value], 7)
)
)
```

## Feedback

https://aka.ms/ContentUserFeedback.

Coming soon: Throughout 2024 we will be phasing out GitHub Issues as the feedback mechanism for content and replacing it with a new feedback system. For more information see:Submit and view feedback for