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LambdaExpressionSyntax.WithBlock(BlockSyntax) Method

Definition

public Microsoft.CodeAnalysis.CSharp.Syntax.LambdaExpressionSyntax WithBlock (Microsoft.CodeAnalysis.CSharp.Syntax.BlockSyntax? block);
override this.WithBlock : Microsoft.CodeAnalysis.CSharp.Syntax.BlockSyntax -> Microsoft.CodeAnalysis.CSharp.Syntax.LambdaExpressionSyntax
Public Function WithBlock (block As BlockSyntax) As LambdaExpressionSyntax

Parameters

block
BlockSyntax

Returns

Applies to