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Possible unintended reference comparison; to get a value comparison, cast the right hand side to type 'type'
The compiler is doing a reference comparison. If you want to compare the value of strings, cast the right side of the expression to type
.
The following sample generates CS0253:
// CS0253.cs
// compile with: /W:2
using System;
class MyClass
{
public static void Main()
{
string s = "11";
object o = s + s;
bool c = s == o; // CS0253
// try the following line instead
// bool c = s == (string)o;
}
}
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