# ^ Operator (Visual Basic)

Raises a number to the power of another number.

## Syntax

```
number ^ exponent
```

## Parts

`number`

Required. Any numeric expression.

`exponent`

Required. Any numeric expression.

## Result

The result is `number`

raised to the power of `exponent`

, always as a `Double`

value.

## Supported Types

`Double`

. Operands of any different type are converted to `Double`

.

## Remarks

Visual Basic always performs exponentiation in the Double Data Type.

The value of `exponent`

can be fractional, negative, or both.

When more than one exponentiation is performed in a single expression, the `^`

operator is evaluated as it is encountered from left to right.

Note

The `^`

operator can be *overloaded*, which means that a class or structure can redefine its behavior when an operand has the type of that class or structure. If your code uses this operator on such a class or structure, be sure you understand its redefined behavior. For more information, see Operator Procedures.

## Example

The following example uses the `^`

operator to raise a number to the power of an exponent. The result is the first operand raised to the power of the second.

```
Dim exp1, exp2, exp3, exp4, exp5, exp6 As Double
exp1 = 2 ^ 2
exp2 = 3 ^ 3 ^ 3
exp3 = (-5) ^ 3
exp4 = (-5) ^ 4
exp5 = 8 ^ (1.0 / 3.0)
exp6 = 8 ^ (-1.0 / 3.0)
```

The preceding example produces the following results:

`exp1`

is set to 4 (2 squared).

`exp2`

is set to 19683 (3 cubed, then that value cubed).

`exp3`

is set to -125 (-5 cubed).

`exp4`

is set to 625 (-5 to the fourth power).

`exp5`

is set to 2 (cube root of 8).

`exp6`

is set to 0.5 (1.0 divided by the cube root of 8).

Note the importance of the parentheses in the expressions in the preceding example. Because of *operator precedence*, Visual Basic normally performs the `^`

operator before any others, even the unary `–`

operator. If `exp4`

and `exp6`

had been calculated without parentheses, they would have produced the following results:

`exp4 = -5 ^ 4`

would be calculated as –(5 to the fourth power), which would result in -625.

`exp6 = 8 ^ -1.0 / 3.0`

would be calculated as (8 to the –1 power, or 0.125) divided by 3.0, which would result in 0.041666666666666666666666666666667.

## See also

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