Replaces a specified number of characters in a
String variable with characters from another string.
Mid( _ ByRef Target As String, _ ByVal Start As Integer, _ Optional ByVal Length As Integer _ ) = StringExpression
Required. Name of the
String variable to modify.
Integer expression. Character position in
Target where the replacement of text begins.
Start uses a one-based index.
Integer expression. Number of characters to replace. If omitted, all of
String is used.
String expression that replaces part of
The number of characters replaced is always less than or equal to the number of characters in
Visual Basic has a Mid function and a
Mid statement. These elements both operate on a specified number of characters in a string, but the
Mid function returns the characters while the
Mid statement replaces the characters. For more information, see Mid.
MidB statement of earlier versions of Visual Basic replaces a substring in bytes, rather than characters. It is used primarily for converting strings in double-byte character set (DBCS) applications. All Visual Basic strings are in Unicode, and
MidB is no longer supported.
This example uses the
Mid statement to replace a specified number of characters in a string variable with characters from another string.
Dim testString As String ' Initializes string. testString = "The dog jumps" ' Returns "The fox jumps". Mid(testString, 5, 3) = "fox" ' Returns "The cow jumps". Mid(testString, 5) = "cow" ' Returns "The cow jumpe". Mid(testString, 5) = "cow jumped over" ' Returns "The duc jumpe". Mid(testString, 5, 3) = "duck"
Assembly: Visual Basic Runtime Library (in Microsoft.VisualBasic.dll)
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