Replaces a specified number of characters in a Variant (String) variable with characters from another string.
Mid(stringvar, start, [ length ] ) = string
The Mid statement syntax has these parts:
|stringvar||Required. Name of string variable to modify.|
|start||Required; Variant (Long). Character position in stringvar where the replacement of text begins.|
|length||Optional; Variant (Long). Number of characters to replace. If omitted, all of string is used.|
|string||Required. String expression that replaces part of stringvar.|
The number of characters replaced is always less than or equal to the number of characters in stringvar.
Use the MidB statement with byte data contained in a string. In the MidB statement, start specifies the byte position within stringvar where replacement begins, and length specifies the numbers of bytes to replace.
This example uses the Mid statement to replace a specified number of characters in a string variable with characters from another string.
Dim MyString MyString = "The dog jumps" ' Initialize string. Mid(MyString, 5, 3) = "fox" ' MyString = "The fox jumps". Mid(MyString, 5) = "cow" ' MyString = "The cow jumps". Mid(MyString, 5) = "cow jumped over" ' MyString = "The cow jumpe". Mid(MyString, 5, 3) = "duck" ' MyString = "The duc jumpe".
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