5.6.9.3.4 * Operator

The * operator returns the product of its two operands.

 multiplication-operator-expression = expression "*" expression 

Static semantics:

§ A * operator expression has the standard static semantics for binary arithmetic operators (section 5.6.9.3) with the following exceptions when determining the operator’s declared type:

Left Operand Declared Type	Right Operand Declared Type	Operator Declared Type
Currency	Single, Double, String or String * length	Double
Single, Double, String or String * length	Currency	Double
Date	Any numeric type, String, String * length or Date	Double
Any numeric type, String, String * length or Date	Date	Double

 

Runtime semantics:

§ A * operator expression has the standard runtime semantics for binary arithmetic operators (section 5.6.9.3) with the following exceptions when determining the operator’s effective value type:

Left Operand Value Type	Right Operand Value Type	Effective Value Type
Currency	Single, Double or String	Double
Single, Double or String	Currency	Double
Date	Any integral or floating-point numeric type, Currency, String, Date or Empty
Any integral or floating-point numeric type, Currency, String, Date or Empty	Date

 

§ The semantics of the * operator depend on the operator’s effective value type:

Effective Value Type	Runtime Semantics
Byte, Integer, Long, LongLong, Currency or Decimal	The result is the left operand multiplied with the right operand.
Single or Double	The result is the left operand multiplied with the right operand.   If this results in multiplying positive or negative infinity by 0, runtime error 6 (Overflow) is raised. In this case, if this expression was within the right-hand side of a Let assignment and both operands have a declared type of Double, the resulting IEEE 754 Double special value (such as positive/negative infinity or NaN) is assigned before raising the runtime error.
Null	The result is the value Null.