Number.Mod
Number.Mod(number as nullable number, divisor as nullable number, optional precision as nullable number) as nullable number
Returns the remainder resulting from the integer division of number
by divisor
. If number
or divisor
are null, Number.Mod
returns null.
number
: The dividend.divisor
: The divisor.
Find the remainder when you divide 5 by 3.
Usage
Number.Mod(5, 3)
Output
2