Table.Partition
Table.Partition(table as table, column as text, groups as number, hash as function) as list
Partitions the table
into a list of groups
number of tables, based on the value of the column
and a hash
function. The hash
function is applied to the value of the column
row to obtain a hash value for the row. The hash value modulo groups
determines in which of the returned tables the row will be placed.
table
: The table to partition.column
: The column to hash to determine which returned table the row is in.groups
: The number of tables the input table will be partitioned into.hash
: The function applied to obtain a hash value.
Partition the table ({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]})
into 2 tables on column [a], using the value of the columns as the hash function.
Usage
Table.Partition(
Table.FromRecords({
[a = 2, b = 4],
[a = 1, b = 4],
[a = 2, b = 4],
[a = 1, b = 4]
}),
"a",
2,
each _
)
Output
{
Table.FromRecords({
[a = 2, b = 4],
[a = 2, b = 4]
}),
Table.FromRecords({
[a = 1, b = 4],
[a = 1, b = 4]
})
}