# Table.PositionOfAny

## Syntax

Table.PositionOfAny(tableas table,rowsas list, optionaloccurrenceas nullable number, optionalequationCriteriaas any) as any

## About

Returns the row(s) position(s) from the `table`

of the first occurrence of the list of `rows`

. Returns -1 if no occurrence is found.

`table`

: The input table.`rows`

: The list of rows in the table to find the positions of.`occurrence`

:*[Optional]*Specifies which occurrences of the row to return.- `equationCriteria:
*[Optional]*Controls the comparison between the table rows.

## Example 1

Find the position of the first occurrence of [a = 2, b = 4] or [a = 6, b = 8] in the table `({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]})`

.

**Usage**

```
Table.PositionOfAny(
Table.FromRecords({
[a = 2, b = 4],
[a = 1, b = 4],
[a = 2, b = 4],
[a = 1, b = 4]
}),
{
[a = 2, b = 4],
[a = 6, b = 8]
}
)
```

**Output**

`0`

## Example 2

Find the position of all the occurrences of [a = 2, b = 4] or [a = 6, b = 8] in the table `({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]}`

.

**Usage**

```
Table.PositionOfAny(
Table.FromRecords({
[a = 2, b = 4],
[a = 6, b = 8],
[a = 2, b = 4],
[a = 1, b = 4]
}),
{
[a = 2, b = 4],
[a = 6, b = 8]
},
Occurrence.All
)
```

**Output**

`{0, 1, 2}`

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