# Table.PositionOfAny

## Syntax

```
Table.PositionOfAny(table as table, rows as list, optional occurrence as nullable number, optional equationCriteria as any) as any
```

Returns the row(s) position(s) from the `table` of the first occurrence of the list of `rows`. Returns -1 if no occurrence is found.

• `table`: The input table.
• `rows`: The list of rows in the table to find the positions of.
• `occurrence`: [Optional] Specifies which occurrences of the row to return.
• `equationCriteria: [Optional] Controls the comparison between the table rows.

## Example 1

Find the position of the first occurrence of [a = 2, b = 4] or [a = 6, b = 8] in the table `({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]})`.

Usage

``````Table.PositionOfAny(
Table.FromRecords({
[a = 2, b = 4],
[a = 1, b = 4],
[a = 2, b = 4],
[a = 1, b = 4]
}),
{
[a = 2, b = 4],
[a = 6, b = 8]
}
)
``````

Output

`0`

## Example 2

Find the position of all the occurrences of [a = 2, b = 4] or [a = 6, b = 8] in the table `({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]}`.

Usage

``````Table.PositionOfAny(
Table.FromRecords({
[a = 2, b = 4],
[a = 6, b = 8],
[a = 2, b = 4],
[a = 1, b = 4]
}),
{
[a = 2, b = 4],
[a = 6, b = 8]
},
Occurrence.All
)
``````

Output

`{0, 1, 2}`