DatePart Function

Returns the specified part of a given date.

                      DatePart(interval, date[, firstdayofweek[, firstweekofyear]])

Arguments

• interval
  Required. String expression that is the interval of time you want to return. See Settings section for values.

• date
  Required. Date expression you want to evaluate.

• firstdayof week
  Optional. Constant that specifies the day of the week. If not specified, Sunday is assumed. See Settings section for values.

• firstweekofyear
  Optional. Constant that specifies the first week of the year. If not specified, the first week is assumed to be the week in which January 1 occurs. See Settings section for values.

Settings

The interval argument can have the following values:

Setting	Description
yyyy	Year
q	Quarter
m	Month
y	Day of year
d	Day
w	Weekday
ww	Week of year
h	Hour
n	Minute
s	Second

The firstdayofweek argument can have the following values:

Constant	Value	Description
vbUseSystemDayOfWeek	0	Use National Language Support (NLS) API setting.
vbSunday	1	Sunday (default)
vbMonday	2	Monday
vbTuesday	3	Tuesday
vbWednesday	4	Wednesday
vbThursday	5	Thursday
vbFriday	6	Friday
vbSaturday	7	Saturday

The firstweekofyear argument can have the following values:

Constant	Value	Description
vbUseSystem	0	Use National Language Support (NLS) API setting.
vbFirstJan1	1	Start with the week in which January 1 occurs (default).
vbFirstFourDays	2	Start with the week that has at least four days in the new year.
vbFirstFullWeek	3	Start with the first full week of the new year.

Remarks

You can use the DatePart function to evaluate a date and return a specific interval of time. For example, you might use DatePart to calculate the day of the week or the current hour.

The firstdayofweek argument affects calculations that use the "w" and "ww" interval symbols.

When you use the "w" interval symbol, the weekday value that is returned is 1 for Sunday, 2 for Monday, and so on (unless a firstdayofweek argument is provided).

When you use the "h" interval symbol, the hour that is returned is based on a 24-hour clock, and does not contain A.M. or P.M.

If date is a date literal, the specified year becomes a permanent part of that date. However, if date is enclosed in quotation marks (" "), and you omit the year, the current year is inserted in your code each time the date expression is evaluated. This makes it possible to write code that can be used in different years.

Example

The following example illustrates the use of the DatePart function.

Dim Quarter, DayOfYear, WeekOfYear

Quarter    = DatePart("q", Now)
DayOfYear  = DatePart("y", Now)
WeekOfYear = DatePart("ww", Now)

Requirements

Version 2

See Also

Reference

DateAdd Function

DateDiff Function

Month Function

Hour Function

Change History

Date	History	Reason
August 2009	Modified the example.	Customer feedback.
March 2009	Added additional information about the "w" and "h" interval symbols.	Information enhancement.