PenInputPanel.Left Property

Article
12/12/2007

Deprecated. Gets the horizontal, or x-axis, location of the left edge of the PenInputPanel object, in screen coordinates. PenInputPanel has been replaced by Microsoft.Ink.TextInput.

Namespace: Microsoft.Ink
Assembly: Microsoft.Ink (in microsoft.ink.dll)

Syntax

'Declaration
Public ReadOnly Property Left As Integer
'Usage
Dim instance As PenInputPanel
Dim value As Integer

value = instance.Left

public int Left { get; }

public:
property int Left {
    int get ();
}

/** @property */
public int get_Left ()

public function get Left () : int

Not applicable.

Property Value

The horizontal, or x-axis, location of the left edge of the PenInputPanel object, in screen coordinates.

Remarks

To explicitly override the automatic positioning behavior of the PenInputPanel object, use the Left and Top properties of the object to determine the current position of the pen input panel.

You can also override the automatic positioning behavior of the PenInputPanel object by listening for the Left and Top properties of the PenInputPanelMovingEventArgs object during a PanelMoving event.

Security Note:
If using under partial trust, this property requires SecurityPermissionFlag.AllFlags permission, in addition to the permissions required by PenInputPanel. See Security and Trust for more information.

Example

This C# example creates a PenInputPanel object, thePenInputPanel, and attaches it to an InkEdit control, theInkEdit. It then attaches a VisibleChanged event handler, VisibleChanged_Event. The event handler uses the Left property to add a sentence to the content of theInkEdit, stating where the left edge of the PenInputPanel object is located, in screen coordinates.

[C#]

//...

// Declare the PenInputPanel object
PenInputPanel thePenInputPanel;

public Form1()
{
    // Required for Windows Form Designer support
    InitializeComponent();

    // Create and attach the new PenInputPanel to an InkEdit control.
    thePenInputPanel = new PenInputPanel(theInkEdit);

    // Add a VisibleChanged event handler
    thePenInputPanel.VisibleChanged +=
        new PenInputPanelVisibleChangedEventHandler(VisibleChanged_Event);
}

//...

public void VisibleChanged_Event(object sender,
                                 PenInputPanelVisibleChangedEventArgs e)
{
    // Make sure the object that generated
    // the event is a PenInputPanel object
    if (sender is PenInputPanel)
    {
        PenInputPanel theSenderPanel = (PenInputPanel)sender;

        // When the panel has become visible...
        if (e.NewVisibility)
        {
            // Display the left edge of the
            // panel in the attached edit control
            theSenderPanel.AttachedEditControl.Text +=
                    "The left edge of the panel is at ";
            theSenderPanel.AttachedEditControl.Text += theSenderPanel.Left.ToString();
            theSenderPanel.AttachedEditControl.Text += " pixels.\n";
        }
    }
}

This Microsoft® Visual Basic® .NET example creates a PenInputPanel object, thePenInputPanel, and attaches it to an InkEdit control, theInkEdit. It then attaches a VisibleChanged event handler, VisibleChanged_Event. The event handler uses the Left property to add a sentence to the content of theInkEdit, stating where the left edge of the PenInputPanel object is located, in screen coordinates.

[Visual Basic]

'...

' Declare the PenInputPanel object
Dim thePenInputPanel As PenInputPanel

Public Sub New()
    MyBase.New()

    ' Required for Windows Form Designer support
    InitializeComponent()

    ' Create and attach the new PenInputPanel to an InkEdit control.
    thePenInputPanel = New PenInputPanel(theInkEdit)

    ' Add a VisibleChanged event handler
    AddHandler thePenInputPanel.VisibleChanged, _
               AddressOf VisibleChanged_Event
End Sub 'New

'...

Public Sub VisibleChanged_Event(sender As Object, e As _
                                PenInputPanelVisibleChangedEventArgs)
    ' Make sure the object that generated
    ' the event is a PenInputPanel object
    If TypeOf sender Is PenInputPanel Then
       Dim theSenderPanel As PenInputPanel = CType(sender, PenInputPanel)

       ' When the panel has become visible...
       If e.NewVisibility Then
           ' Display the left edge of the
           ' panel in the attached edit control
           theSenderPanel.AttachedEditControl.Text += _
                    "The left edge of the panel is at "
          theSenderPanel.AttachedEditControl.Text += _
                   theSenderPanel.Left.ToString()
          theSenderPanel.AttachedEditControl.Text += _
                   " pixels." + ControlChars.Lf
       End If
    End If
End Sub 'VisibleChanged_Event

Platforms

Windows 98, Windows Server 2000 SP4, Windows CE, Windows Millennium Edition, Windows Mobile for Pocket PC, Windows Mobile for Smartphone, Windows Server 2003, Windows XP Media Center Edition, Windows XP Professional x64 Edition, Windows XP SP2, Windows XP Starter Edition

The Microsoft .NET Framework 3.0 is supported on Windows Vista, Microsoft Windows XP SP2, and Windows Server 2003 SP1.

Version Information

.NET Framework

Supported in: 3.0

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