XYToLocation method
Returns the Location object for the specified screen coordinates.
Applies to
Objects: Map
Syntax
object.XYToLocation(X, Y)
Parameters
Part | Description |
---|---|
object | Required. An expression that returns a Map object. |
X | Required Long. The X coordinate of the desired location on the screen, in pixels. |
Y | Required Long. The Y coordinate of the desired location on the screen, in pixels. |
Example
Sub ShowDistanceNYToLA()
Dim objApp As New MapPoint.Application
Dim objMap As MapPoint.Map
Dim objLocNY As MapPoint.Location
Dim objLocLA As MapPoint.Location
Dim objCenter As MapPoint.Location
Dim objTextbox As MapPoint.Shape
'Set up application and create Location objects
Let objApp.Visible = True
Let objApp.UserControl = True
Set objMap = objApp.ActiveMap
Set objLocNY = objMap.FindResults("New York, NY").Item(1)
Set objLocLA = objMap.FindResults("Los Angeles, CA").Item(1)
'Find the point on the screen midway between the two
X1% = objMap.LocationToX(objLocNY)
Y1% = objMap.LocationToY(objLocNY)
X2% = objMap.LocationToX(objLocLA)
Y2% = objMap.LocationToY(objLocLA)
x% = (X1% + X2%) / 2
y% = (Y1% + Y2%) / 2
Set objCenter = objMap.XYToLocation(x%, y%)
'Show the distance
objMap.Shapes.AddLine objLocNY, objLocLA
Set objTextbox = objMap.Shapes.AddTextbox(objCenter, 200, 50)
Distance# = objMap.Distance(objLocNY, objLocLA)
Let objTextbox.Text = "Distance, New York to Los Angeles: " & Distance#
End Sub
Note This sample code is specific for use in MapPoint North America; it is for illustration purposes only.