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FormTemplate.OpenFileFromPackage Method (Microsoft.Office.InfoPath)

  • Article

Opens a file contained within the form template (.xsn) file.

Namespace: Microsoft.Office.InfoPath
Assembly: Microsoft.Office.InfoPath (in microsoft.office.infopath.dll)

Syntax

'Declaration
Public MustOverride Function OpenFileFromPackage ( _
    filename As String _
) As Stream
'Usage
Dim instance As FormTemplate
Dim filename As String
Dim returnValue As Stream

returnValue = instance.OpenFileFromPackage(filename)

public abstract Stream OpenFileFromPackage (
    string filename
)

Parameters

  • filename
    The name of the file to open.

Return Value

The specified file as a Stream object.

Exceptions

Exception type Condition

IOException

An I/O error, such as file not found.

ArgumentNullException

The parameter passed to this method is null.

ArgumentException

The parameter passed to this method isnot valid. For example, it is of the wrong type or format.

Remarks

This member can be accessed only by forms running in the same domain as the currently open form, or by forms that have been granted cross-domain permissions.

This type or member can be accessed from code running in forms opened in Microsoft Office InfoPath 2007 or in a Web browser.

See Also

Reference

FormTemplate Class
FormTemplate Members
Microsoft.Office.InfoPath Namespace