Document.FullBuildNumberEdited Property (Visio)
Returns the full build number of the instance last used to edit the document. Read-only.
Version Information
Version Added: Visio 2002
Syntax
expression .FullBuildNumberEdited
expression A variable that represents a Document object.
Return Value
Long
Remarks
The format of the full build number is described in the following table.
Bits |
Description |
---|---|
0 - 15 |
Internal build number |
16 - 20 |
Internal revision number |
21 - 25 |
Minor version number. |
26 - 30 |
Major version number (Visio 2010 = 14) |
31 |
Reserved |
In addition, for Microsoft Visio 2010, to obtain the correct full build number, it is necessary to add 1000 to the internal revision number part of the full build number returned by the FullBuildNumberEdited property, as shown in the following macro.
Example
The following Microsoft Visual Basic procedures show how to use the FullBuildNumberEdited property to get the full build number of the instance of Visio last used to edit the document. When the full build number has been obtained, the ParseFullBuildNumberEditedProperty procedure parses the number and prints the result in the Immediate window.
Public Sub FullBuildNumberEdited_Example()
Dim lngFullBuild As Long
lngFullBuild = ActiveDocument.FullBuildNumberEdited
ParseFullBuildNumberEditedProperty (lngFullBuild)
End Sub
Public Sub ParseFullBuildNumberEditedProperty(ByRef lngFullBuild As Long)
Dim lngMajor As Long
Dim lngMinor As Long
Dim lngRevision As Long
Dim lngBuild As Long
Dim lngNumber As Long
lngNumber = lngFullBuild
' Low 16 bits:
lngBuild = lngNumber Mod 65536
lngNumber = lngNumber / 65536
'Next 5 bits:
lngRevision = lngNumber Mod 32
lngNumber = lngNumber / 32
'Next 5 bits:
lngMinor = lngNumber Mod 32
lngNumber = lngNumber / 32
'Next 5 bits:
lngMajor = lngNumber Mod 32
lngNumber = lngNumber / 32
'Remaining 1 bit unused and 0 as of Visio 2010
Debug.Print "lngFullBuild (full version specification): " & lngMajor & "." _
& lngMinor & "." & lngBuild & "." & lngRevision + 1000
Debug.Assert(0 = lngNumber)
End Sub