How to: Find Descendant Elements (XPath-LINQ to XML)
This topic shows how to get the descendant elements with a particular name.
The XPath expression is //Name.
Example
This example finds all descendants named Name.
This example uses the following XML document: Sample XML File: Multiple Purchase Orders (LINQ to XML).
XDocument po = XDocument.Load("PurchaseOrders.xml");
// LINQ to XML query
IEnumerable<XElement> list1 = po.Root.Descendants("Name");
// XPath expression
IEnumerable<XElement> list2 = po.XPathSelectElements("//Name");
if (list1.Count() == list2.Count() &&
list1.Intersect(list2).Count() == list1.Count())
Console.WriteLine("Results are identical");
else
Console.WriteLine("Results differ");
foreach (XElement el in list1)
Console.WriteLine(el);
Dim po As XDocument = XDocument.Load("PurchaseOrders.xml")
' LINQ to XML query
Dim list1 As IEnumerable(Of XElement) = po...<Name>
' XPath expression
Dim list2 As IEnumerable(Of XElement) = po.XPathSelectElements("//Name")
If (list1.Count() = list2.Count() And _
list1.Intersect(list2).Count() = list1.Count()) Then
Console.WriteLine("Results are identical")
Else
Console.WriteLine("Results differ")
End If
For Each el As XElement In list1
Console.WriteLine(el)
Next
This example produces the following output:
Results are identical
<Name>Ellen Adams</Name>
<Name>Tai Yee</Name>
<Name>Cristian Osorio</Name>
<Name>Cristian Osorio</Name>
<Name>Jessica Arnold</Name>
<Name>Jessica Arnold</Name>