Example that Outputs Office Open XML Document Parts

This topic shows how to open an Office Open XML document and access parts within it.

Example

The following example opens an Office Open XML document, and prints the document part and the style part to the console.

This example uses classes from the WindowsBase assembly. It uses types in the System.IO.Packaging namespace.

const string fileName = "SampleDoc.docx";

const string documentRelationshipType =
  "https://schemas.openxmlformats.org/officeDocument/2006/relationships/officeDocument";
const string stylesRelationshipType =
  "https://schemas.openxmlformats.org/officeDocument/2006/relationships/styles";
const string wordmlNamespace =
  "https://schemas.openxmlformats.org/wordprocessingml/2006/main";
XNamespace w = wordmlNamespace;

using (Package wdPackage = Package.Open(fileName, FileMode.Open, FileAccess.Read))
{
    PackageRelationship docPackageRelationship =
      wdPackage.GetRelationshipsByType(documentRelationshipType).FirstOrDefault();
    if (docPackageRelationship != null)
    {
        Uri documentUri = PackUriHelper.ResolvePartUri(new Uri("/", UriKind.Relative),
          docPackageRelationship.TargetUri);
        PackagePart documentPart = wdPackage.GetPart(documentUri);

        //  Load the document XML in the part into an XDocument instance.
        XDocument xdoc = XDocument.Load(XmlReader.Create(documentPart.GetStream()));

        Console.WriteLine("TargetUri:{0}", docPackageRelationship.TargetUri);
        Console.WriteLine("==================================================================");
        Console.WriteLine(xdoc.Root);
        Console.WriteLine();

        //  Find the styles part. There will only be one.
        PackageRelationship styleRelation =
          documentPart.GetRelationshipsByType(stylesRelationshipType).FirstOrDefault();
        if (styleRelation != null)
        {
            Uri styleUri = PackUriHelper.ResolvePartUri(documentUri, styleRelation.TargetUri);
            PackagePart stylePart = wdPackage.GetPart(styleUri);

            //  Load the style XML in the part into an XDocument instance.
            XDocument styleDoc = XDocument.Load(XmlReader.Create(stylePart.GetStream()));

            Console.WriteLine("TargetUri:{0}", styleRelation.TargetUri);
            Console.WriteLine("==================================================================");
            Console.WriteLine(styleDoc.Root);
            Console.WriteLine();
        }
    }
}

Const fileName As String = "SampleDoc.docx"

Const documentRelationshipType As String = _
  "https://schemas.openxmlformats.org/officeDocument/2006/relationships/officeDocument"
Const stylesRelationshipType As String = _
  "https://schemas.openxmlformats.org/officeDocument/2006/relationships/styles"
Const wordmlNamespace As String = _
  "https://schemas.openxmlformats.org/wordprocessingml/2006/main"
Dim w As XNamespace = wordmlNamespace

Using wdPackage As Package = Package.Open(fileName, FileMode.Open, FileAccess.Read)
    Dim docPackageRelationship As PackageRelationship = _
      wdPackage.GetRelationshipsByType(documentRelationshipType).FirstOrDefault()
    If docPackageRelationship IsNot Nothing Then
        Dim documentUri As Uri = PackUriHelper.ResolvePartUri(New Uri("/", UriKind.Relative), _
          docPackageRelationship.TargetUri)
        Dim documentPart As PackagePart = wdPackage.GetPart(documentUri)

        ' Load the document XML in the part into an XDocument instance.
        Dim xdoc As XDocument = XDocument.Load(XmlReader.Create(documentPart.GetStream()))

        Console.WriteLine("TargetUri:{0}", docPackageRelationship.TargetUri)
        Console.WriteLine("==================================================================")
        Console.WriteLine(xdoc.Root)
        Console.WriteLine()

        ' Find the styles part. There will only be one.
        Dim styleRelation As PackageRelationship = _
          documentPart.GetRelationshipsByType(stylesRelationshipType).FirstOrDefault()
        If styleRelation IsNot Nothing Then
            Dim styleUri As Uri = _
              PackUriHelper.ResolvePartUri(documentUri, styleRelation.TargetUri)
            Dim stylePart As PackagePart = wdPackage.GetPart(styleUri)

            ' Load the style XML in the part into an XDocument instance.
            Dim styleDoc As XDocument = XDocument.Load(XmlReader.Create(stylePart.GetStream()))

            Console.WriteLine("TargetUri:{0}", styleRelation.TargetUri)
            Console.WriteLine("==================================================================")
            Console.WriteLine(styleDoc.Root)
            Console.WriteLine()
        End If
    End If
End Using

See Also

Concepts

Details of Office Open XML WordprocessingML Documents