has_virtual_destructor Class

Tests if type has virtual destructor.

template<class Ty>
    struct has_virtual_destructor;

Parameters

• Ty
  The type to query.

Remarks

An instance of the type predicate holds true if the type Ty is a class that has a virtual destructor, otherwise it holds false.

Example

 

// std_tr1__type_traits__has_virtual_destructor.cpp 
// compile with: /EHsc 
#include <type_traits> 
#include <iostream> 
 
struct trivial 
    { 
    int val; 
    }; 
 
struct throws 
    { 
    throws() throw(int) 
        { 
        } 
 
    throws(const throws&) throw(int) 
        { 
        } 
 
    throws& operator=(const throws&) throw(int) 
        { 
        } 
 
    virtual ~throws() 
        { 
        } 
 
    int val; 
    }; 
 
int main() 
    { 
    std::cout << "has_virtual_destructor<trivial> == " << std::boolalpha 
        << std::tr1::has_virtual_destructor<trivial>::value << std::endl; 
    std::cout << "has_virtual_destructor<throws> == " << std::boolalpha 
        << std::tr1::has_virtual_destructor<throws>::value << std::endl; 
 
    return (0); 
    } 
 

has_virtual_destructor<trivial> == false has_virtual_destructor<throws> == true

Requirements

Header: <type_traits>

Namespace: std::tr1

See Also

Reference

<type_traits>

has_trivial_destructor Class