UTC Method
Returns the number of milliseconds between midnight, January 1, 1970 Coordinated Universal Time (UTC) (or GMT) and the supplied date.
function UTC(year : Number , month : Number , day : Number [, hours : Number [, minutes : Number [, seconds : Number [,ms : Number]]]]) : Number
Arguments
year
Required. The full year designation is required for cross-century date accuracy. If year is between 0 and 99 is used, then year is assumed to be 1900 + year.month
Required. The month as an integer between 0 and 11 (January to December).day
Required. The date as an integer between 1 and 31.hours
Optional. Must be supplied if minutes is supplied. An integer from 0 to 23 (midnight to 11pm) that specifies the hour.minutes
Optional. Must be supplied if seconds is supplied. An integer from 0 to 59 that specifies the minutes.seconds
Optional. Must be supplied if milliseconds is supplied. An integer from 0 to 59 that specifies the seconds.ms
Optional. An integer from 0 to 999 that specifies the milliseconds.
Remarks
The UTC method returns the number of milliseconds between midnight, January 1, 1970 UTC and the supplied date. This return value can be used in the setTime method and in the Date object constructor. If the value of an argument is greater than its range, or is a negative number, other stored values are modified accordingly. For example, if you specify 150 seconds, JScript redefines that number as two minutes and 30 seconds.
The difference between the UTC method and the Date object constructor that accepts a date is that the UTC method assumes UTC, and the Date object constructor assumes local time.
The UTC method is a static method. Therefore, a Date object does not have to be created before it can be used.
Example
The following example illustrates the use of the UTC method.
function DaysBetweenDateAndNow(yr, mo, dy)
{
// Determine the milliseconds per day.
var MinMilli = 1000 * 60
var HrMilli = MinMilli * 60
var DyMilli = HrMilli * 24
// Determine today's UTC year, month, and day.
var d = new Date();
var yeartoday = d.getUTCFullYear();
var monthtoday = d.getUTCMonth();
var dayofmonthtoday = d.getUTCDate();
// Get the milliseconds since 1/1/1970 UTC.
var t1 = Date.UTC(yr, mo - 1, dy)
var t2 = Date.UTC(yeartoday, monthtoday, dayofmonthtoday);
// Determine the difference in days.
var days = (t1 - t2) / DyMilli;
return(days);
}
Requirements
Applies To:
See Also
Reference
Change History
Date |
History |
Reason |
---|---|---|
March 2009 |
Modified example. |
Content bug fix. |