Video.Open Method ()

Loads a new file into the Video object.

Overload List

public void Open(string);

public void Open(string, bool);

public void Open(Uri);

public void Open(Uri, bool);

Remarks

Exceptions

DirectXException

For more information on the cause of this exception, reference the DirectXException.ErrorCode and DirectXException.ErrorString properties to the AudioVideoPlayback error code table.