String.Concat Method (Object, Object)
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Updated: October 2010
Concatenates the string representations of two specified objects.
Namespace: System
Assembly: mscorlib (in mscorlib.dll)
Syntax
'Declaration
Public Shared Function Concat ( _
arg0 As Object, _
arg1 As Object _
) As String
public static string Concat(
Object arg0,
Object arg1
)
Parameters
- arg0
Type: System.Object
The first object to concatenate.
- arg1
Type: System.Object
The second object to concatenate.
Return Value
Type: System.String
The concatenated string representations of the values of arg0 and arg1.
Remarks
The method concatenates arg0 and arg1 by calling the parameterless ToString method of arg0 and arg1; it does not add any delimiters.
String.Empty is used in place of any null argument.
If either of the arguments is an array reference, the method concatenates a string representing that array, instead of its members (for example, "System.String[]").
Examples
The following code example demonstrates the Concat method.
_
Class Example
Public Shared Sub Demo(ByVal outputBlock As System.Windows.Controls.TextBlock)
Dim i As Integer = -123
Dim o As [Object] = i
Dim objs() As [Object] = {-123, -456, -789}
outputBlock.Text += String.Format("Concatenate 1, 2, and 3 objects:") & vbCrLf
outputBlock.Text += String.Format("1) {0}", [String].Concat(o)) & vbCrLf
outputBlock.Text += String.Format("2) {0}", [String].Concat(o, o)) & vbCrLf
outputBlock.Text += String.Format("3) {0}", [String].Concat(o, o, o)) & vbCrLf
outputBlock.Text &= vbCrLf & "Concatenate 4 objects and a variable length parameter list:" & vbCrLf
outputBlock.Text += String.Format("4) {0}", [String].Concat(o, o, o, o, o)) & vbCrLf
outputBlock.Text &= vbCrLf & "Concatenate a 3 element object array:" & vbCrLf
outputBlock.Text += String.Format("5) {0}", [String].Concat(objs)) & vbCrLf
End Sub 'Main
End Class 'stringConcat5
'
'This example produces the following output:
'Concatenate 1, 2, and 3 objects:
'1) -123
'2) -123-123
'3) -123-123-123
'
'Concatenate 4 objects and a variable length parameter list:
'4) -123-123-123-123-123
'
'Concatenate a 3 element object array:
'5) -123-456-789
'
using System;
class Example
{
public static void Demo(System.Windows.Controls.TextBlock outputBlock)
{
int i = -123;
Object o = i;
Object[] objs = new Object[] { -123, -456, -789 };
outputBlock.Text += String.Format("Concatenate 1, 2, and 3 objects:") + "\n";
outputBlock.Text += String.Format("1) {0}", String.Concat(o)) + "\n";
outputBlock.Text += String.Format("2) {0}", String.Concat(o, o)) + "\n";
outputBlock.Text += String.Format("3) {0}", String.Concat(o, o, o)) + "\n";
outputBlock.Text += "\nConcatenate 4 objects and a variable length parameter list:" + "\n";
outputBlock.Text += String.Format("4) {0}", String.Concat(o, o, o, o, o)) + "\n";
outputBlock.Text += "\nConcatenate a 3 element object array:" + "\n";
outputBlock.Text += String.Format("5) {0}", String.Concat(objs)) + "\n";
}
}
/*
This example produces the following output:
Concatenate 1, 2, and 3 objects:
1) -123
2) -123-123
3) -123-123-123
Concatenate 4 objects and a variable length parameter list:
4) -123-123-123-123-123
Concatenate a 3 element object array:
5) -123-456-789
*/
Version Information
Silverlight
Supported in: 5, 4, 3
Silverlight for Windows Phone
Supported in: Windows Phone OS 7.1, Windows Phone OS 7.0
XNA Framework
Supported in: Xbox 360, Windows Phone OS 7.0
Platforms
For a list of the operating systems and browsers that are supported by Silverlight, see Supported Operating Systems and Browsers.
Change History
Date |
History |
Reason |
---|---|---|
October 2010 |
Revised the Remarks section. |
Customer feedback. |