I am having an issue , the textbov does allow space when pressing space bar

Question

								<TextBox

									x:Name="txtLocationName"

									Grid.Column="3"

									Grid.Row="5"

									Height="22"

									VerticalAlignment="Center"

									TabIndex="17"

									IsEnabled="{Binding boolEnableLocationName}"

									Text="{Binding Path=strSearchLocationNameCaller, Mode=TwoWay,UpdateSourceTrigger=PropertyChanged,NotifyOnSourceUpdated=True}"

									PreviewKeyDown="txtLocationName_PreviewKeyDown"></TextBox>

Answer 1

Hi,@Sgcino Ngema. Welcome to Microsoft Q&A. 

Note: The space bar is also a normal input in a TextBox.

 

If you want to enter data without preserving space bar, you could try using Trim().

 

Here is a reference example:

<Grid>

    <TextBox x:Name="txtLocationName" Grid.Column="3" Grid.Row="5" Height="22" VerticalAlignment="Center" TabIndex="17" IsEnabled="{Binding BoolEnableLocationName}"
        Text="{Binding Path=StrSearchLocationNameCaller, Mode=TwoWay,UpdateSourceTrigger=PropertyChanged,NotifyOnSourceUpdated=True}"
        PreviewKeyDown="txtLocationName_PreviewKeyDown">
    </TextBox>

</Grid>

 

public partial class CaptureUC : UserControl,INotifyPropertyChanged

{

   public event PropertyChangedEventHandler PropertyChanged;

 

    private string strSearchLocationNameCaller;

 

    public string StrSearchLocationNameCaller { get { return strSearchLocationNameCaller; } set { strSearchLocationNameCaller = value.Trim(); OnPropertyChanged("StrSearchLocationNameCaller"); } }

 

    private bool boolEnableLocationName;

 

    public bool BoolEnableLocationName { get { return boolEnableLocationName; } set { boolEnableLocationName = value; OnPropertyChanged("BoolEnableLocationName"); } }

 

    public CaptureUC()

    {

        InitializeComponent();

        BoolEnableLocationName = true;

        this.DataContext = this;

    }

 

    private void txtLocationName_PreviewKeyDown(object sender, KeyEventArgs e)

    {

           

    }

 

    private void OnPropertyChanged(string name)

    {

        PropertyChanged?.Invoke(this, new PropertyChangedEventArgs(name));

    }

}

---

If the answer is the right solution, please click "Accept Answer" and kindly upvote it. If you have extra questions about this answer, please click "Comment".

Note: Please follow the steps in our documentation to enable e-mail notifications if you want to receive the related email notification for this thread.