HttpRequestExecutor.PreProcess Método

Definición

Prepare una solicitud para el envío.

[Android.Runtime.Register("preProcess", "(Lorg/apache/http/HttpRequest;Lorg/apache/http/protocol/HttpProcessor;Lorg/apache/http/protocol/HttpContext;)V", "GetPreProcess_Lorg_apache_http_HttpRequest_Lorg_apache_http_protocol_HttpProcessor_Lorg_apache_http_protocol_HttpContext_Handler")]
public virtual void PreProcess(Org.Apache.Http.IHttpRequest? request, Org.Apache.Http.Protocol.IHttpProcessor? processor, Org.Apache.Http.Protocol.IHttpContext? context);
[<Android.Runtime.Register("preProcess", "(Lorg/apache/http/HttpRequest;Lorg/apache/http/protocol/HttpProcessor;Lorg/apache/http/protocol/HttpContext;)V", "GetPreProcess_Lorg_apache_http_HttpRequest_Lorg_apache_http_protocol_HttpProcessor_Lorg_apache_http_protocol_HttpContext_Handler")>]
abstract member PreProcess : Org.Apache.Http.IHttpRequest * Org.Apache.Http.Protocol.IHttpProcessor * Org.Apache.Http.Protocol.IHttpContext -> unit
override this.PreProcess : Org.Apache.Http.IHttpRequest * Org.Apache.Http.Protocol.IHttpProcessor * Org.Apache.Http.Protocol.IHttpContext -> unit

Parámetros

request
IHttpRequest

la solicitud de preparación

processor
IHttpProcessor

procesador que se va a usar

context
IHttpContext

el contexto para enviar la solicitud

Atributos

Excepciones

en caso de un problema de procesamiento o protocolo

en caso de un problema de E/S

Comentarios

Las partes de esta página son modificaciones basadas en el trabajo creado y compartido por el Android y se usan según los términos descritos en creative Creative Commons 2.5 Attribution License.

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