set::erase
Quita un elemento o un intervalo de elementos de un conjunto de las posiciones especificadas o quita los elementos que coinciden con una clave especificada.
iterator erase(
const_iterator Where
);
iterator erase(
const_iterator First,
const_iterator Last
);
size_type erase(
const key_type& Key
);
Parámetros
Where
Posición del elemento que se va a quitar.First
Posición del primer elemento que se va a quitar.Last
Posición situada más allá del último elemento que se va a quitar.Key
Valor de clave de los elementos que se van a quitar.
Valor devuelto
Para las dos primeras funciones miembro, iterador bidireccional que designa el primer elemento que permanece más allá de los elementos quitados, o un elemento que es el final del conjunto si no existe ese elemento.
Para la tercera función miembro, devuelve el número de elementos que se han quitado del conjunto.
Ejemplo
// set_erase.cpp
// compile with: /EHsc
#include <set>
#include <string>
#include <iostream>
#include <iterator> // next() and prev() helper functions
using namespace std;
using myset = set<string>;
void printset(const myset& s) {
for (const auto& iter : s) {
cout << " [" << iter << "]";
}
cout << endl << "size() == " << s.size() << endl << endl;
}
int main()
{
myset s1;
// Fill in some data to test with, one at a time
s1.insert("Bob");
s1.insert("Robert");
s1.insert("Bert");
s1.insert("Rob");
s1.insert("Bobby");
cout << "Starting data of set s1 is:" << endl;
printset(s1);
// The 1st member function removes an element at a given position
s1.erase(next(s1.begin()));
cout << "After the 2nd element is deleted, the set s1 is:" << endl;
printset(s1);
// Fill in some data to test with, one at a time, using an intializer list
myset s2{ "meow", "hiss", "purr", "growl", "yowl" };
cout << "Starting data of set s2 is:" << endl;
printset(s2);
// The 2nd member function removes elements
// in the range [First, Last)
s2.erase(next(s2.begin()), prev(s2.end()));
cout << "After the middle elements are deleted, the set s2 is:" << endl;
printset(s2);
myset s3;
// Fill in some data to test with, one at a time, using emplace
s3.emplace("C");
s3.emplace("C#");
s3.emplace("D");
s3.emplace("D#");
s3.emplace("E");
s3.emplace("E#");
s3.emplace("F");
s3.emplace("F#");
s3.emplace("G");
s3.emplace("G#");
s3.emplace("A");
s3.emplace("A#");
s3.emplace("B");
cout << "Starting data of set s3 is:" << endl;
printset(s3);
// The 3rd member function removes elements with a given Key
myset::size_type count = s3.erase("E#");
// The 3rd member function also returns the number of elements removed
cout << "The number of elements removed from s3 is: " << count << "." << endl;
cout << "After the element with a key of \"E#\" is deleted, the set s3 is:" << endl;
printset(s3);
}
Resultados
Starting data of set s1 is:
[Bert] [Bob] [Bobby] [Rob] [Robert]
size() == 5
After the 2nd element is deleted, the set s1 is:
[Bert] [Bobby] [Rob] [Robert]
size() == 4
Starting data of set s2 is:
[growl] [hiss] [meow] [purr] [yowl]
size() == 5
After the middle elements are deleted, the set s2 is:
[growl] [yowl]
size() == 2
Starting data of set s3 is:
[A] [A#] [B] [C] [C#] [D] [D#] [E] [E#] [F] [F#] [G] [G#]
size() == 13
The number of elements removed from s3 is: 1.
After the element with a key of "E#" is deleted, the set s3 is:
[A] [A#] [B] [C] [C#] [D] [D#] [E] [F] [F#] [G] [G#]
size() == 12
Requisitos
Encabezado: <set>
Espacio de nombres: std