isgraph

Comprueba si un elemento en una configuración regional es un carácter alfanumérico o de puntuación.

template<Class CharType> 
   bool isgraph( 
      CharType _Ch,  
      const locale& _Loc 
   )

Parámetros

• _Ch
  El elemento que se va a probar.

• _Loc
  Configuración regional que contiene el elemento que se va a probar.

Valor devuelto

true si el elemento probado es un alfanumérico o un carácter de puntuación; false si no es.

Comentarios

La función de la plantilla devuelve use_facet<C<CharType> >(_Loc).es(::<graph>, _ChdectypeCharType).

Ejemplo

// locale_is_graph.cpp
// compile with: /EHsc
#include <locale>
#include <iostream>

using namespace std;

int main( )
{
   locale loc ( "German_Germany" );
   bool result1 = isgraph ( 'L', loc );
   bool result2 = isgraph ( '\t', loc );
   bool result3 = isgraph ( '.', loc );

   if ( result1 )
      cout << "The character 'L' in the locale is\n "
           << "an alphanumeric or punctuation character." << endl;
   else
      cout << "The character 'L' in the locale is\n "
           << " not an alphanumeric or punctuation character." << endl;

   if ( result2 )
      cout << "The character 'backslash-t' in the locale is\n "
           << "an alphanumeric or punctuation character." << endl;
   else
      cout << "The character 'backslash-t' in the locale is\n "
           << "not an alphanumeric or punctuation character." << endl;

   if ( result3 )
      cout << "The character '.' in the locale is\n "
           << "an alphanumeric or punctuation character." << endl;
   else
      cout << "The character '.' in the locale is\n "
           << " not an alphanumeric or punctuation character." << endl;
}

Resultados

The character 'L' in the locale is
 an alphanumeric or punctuation character.
The character 'backslash-t' in the locale is
 not an alphanumeric or punctuation character.
The character '.' in the locale is
 an alphanumeric or punctuation character.

Requisitos

configuración regional <deEncabezado: >

Espacio de nombres: std