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LanguageService.IsDebugging Property

Determines if the debugger is active.

Namespace:  Microsoft.VisualStudio.Package
Assemblies:   Microsoft.VisualStudio.Package.LanguageService.9.0 (in Microsoft.VisualStudio.Package.LanguageService.9.0.dll)
  Microsoft.VisualStudio.Package.LanguageService.10.0 (in Microsoft.VisualStudio.Package.LanguageService.10.0.dll)
  Microsoft.VisualStudio.Package.LanguageService (in Microsoft.VisualStudio.Package.LanguageService.dll)

Syntax

'Declaración
Public ReadOnly Property IsDebugging As Boolean
    Get
'Uso
Dim instance As LanguageService
Dim value As Boolean

value = instance.IsDebugging
public bool IsDebugging { get; }
public:
property bool IsDebugging {
    bool get ();
}
member IsDebugging : bool
function get IsDebugging () : boolean

Property Value

Type: System.Boolean
This property returns true if the debugger is active; otherwise, returns false.

Remarks

A debugger is active if the debug mode does not equal DBGMODE_Design (from the DBGMODE enumeration); this is set when Visual Studio calls the OnModeChange method.

This method is typically called from the ViewFilter class to determine if certain actions can or should be taken.

.NET Framework Security

See Also

Reference

LanguageService Class

LanguageService Members

Microsoft.VisualStudio.Package Namespace